<h2>Hello!</h2>
The answer is: A. 4.5 L
<h2>
Why?</h2>
According to the conversion factor which states that:
It means that we have 3.78 L per each gallon or it's equal to say that we 0.26 gallon per each L.The SI unit for liquid volume is the Liter (L)
Let's make the calculations:
So, we have 4.54 L in 1,2 gallons.
Have a nice day!
(a) James has the most momentum which is 294 kgm/s.
(b) The resultant force acting on Basma is 90.78 N.
(c) The time taken for James to stop is 3.2 seconds.
<h3>
Momentum of each person</h3>
Momentum of James: P = mv = 98 x 3 = 294 kgm/s
Momentum of Basma: P = mv = 59 x 4 = 236 kgm/s
<h3>Resultant force of Basma</h3>
F = ma = mv/t = P/t = 236/2.6 = 90.78 N
<h3>Time for James to stop</h3>
F = P/t
t = P/F
t = 294/90.78
t = 3.2 s
Learn more about momentum here: brainly.com/question/7538238
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Answer:
The earth rotates from West to east
Explanation:
- Every planet in our solar system rotates around their axis in West to east direction.
- Only Venus is the only planet which rotates from east to west
The net force on the block acting perpendicular to the incline is
∑ <em>F</em> = <em>n</em> - <em>w</em> cos(29.4°) = 0
where <em>n</em> is the magnitude of the normal force and <em>w</em> = <em>m g</em> is the weight of the block.
The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.
Solve for <em>n</em> :
<em>n</em> = <em>m g</em> cos(29.4°)
<em>n</em> = (6 kg) (9.80 m/s²) cos(29.4°)
<em>n</em> ≈ 51.2 N
Answer:
Lauch velocity (u) = 26.15 m/s
Lauch Angle (θ) = 35°
Explanation:
From the question given above, the following data were obtained:
Range (R) = 65 m
Time of flight (T) = 3 s
Acceleration due to gravity (g) = 10 m/s²
Lauch velocity (u) =?
Lauch Angle (θ) =?
R = u²Sin2θ /g
65 = u² × Sin2θ /10
Recall:
Sin2θ = 2SinθCosθ
65 = u² × 2SinθCosθ / 10
65 = u² × SinθCosθ / 5
Cross multiply
65 × 5 = u² × SinθCosθ
325 = u² × SinθCosθ .....(1)
T = 2uSinθ / g
3 = 2uSinθ / 10
3 = uSinθ / 5
Cross multiply
3 × 5 = uSinθ
15 = u × Sinθ
Divide both side by Sinθ
u = 15 / Sinθ....... (2)
Substitute the value of u in equation (2) into equation (1)
325 = u² × SinθCosθ
u = 15 / Sinθ
325 = (15 / Sinθ)² × SinθCosθ
325 = 225 / Sin²θ × SinθCosθ
325 = 225 × SinθCosθ / Sin²θ
325 = 225 × Cosθ / Sinθ
Cross multiply
325 × Sineθ = 225 × Cosθ
Divide both side by Cosθ
325 × Sineθ / Cosθ = 225
Divide both side by 325
Sineθ / Cosθ = 225 / 325
Sineθ / Cosθ = 0.6923
Recall:
Sineθ / Cosθ = Tanθ
Tanθ = 0.6923
Take the inverse of Tan
θ = Tan¯¹ 0.6923
θ = 35°
Substitute the value of θ into equation (2) to obtain the value of u.
u = 15 / Sinθ
θ = 35°
u = 15 / Sin 35
u = 15 / 0.5736
u = 26.15 m/s
Summary:
Lauch velocity (u) = 26.15 m/s
Lauch Angle (θ) = 35°
