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miskamm [114]
3 years ago
12

a.) Write the equation to represent the path of the football. b.) What is the initial speed of the football? C.) How high was th

e football off the ground when it was kicked? d.) How long will it take for the football to reach 49 feet e.) How long will the football be above 49 feet? f.) How high is the football after 3.5 seconds?

Physics
1 answer:
stepladder [879]3 years ago
8 0

Answer:

I think y = 49x+3.5  

Explanation:

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A wave travels at 13 m/s and the crests are 6 meters apart. How many waves would you see pass you by per second? (round up to th
MrRa [10]

Answer:Number of waves =2.2

Explanation:

The frequency of A wave is defined as the number of waves moving  a fixed point per second which is given as

f=\frac{N}{t}

F= Frequency

N= number of waves

t= time

We first find the frequency

Given velocity of the wave, v = 13m/s

and wavelength, λ as 6meters(distance between two consecutive crest)

, we fiind the frequency using

v= f  λ

frequency = v /  λ

= (13m/s ) / 6

=2.16s-1

f =  \frac{N}{t}

2.16s₋¹=  \frac{N}{1s}

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3 0
3 years ago
Why are hot springs and geysers is found in areas of present or a past activity
Lady_Fox [76]
<span>Hot springs and geysers are often found in areas of present or past volcanic activity. The hot spring forms when water deep underground is heated by a nearby body of magma or hot rock. The hot water rises and collects in a natural pool; when rising hot water and steam become trapped in a narrow crack, pressure builds until the mixture sprays above the surface as a geyser.</span>
7 0
3 years ago
Two identical twins hold on to a rope, one at each end, on a smooth, frictionless ice surface. They skate in a circle about the
777dan777 [17]

Answer:

Part a)

L = 2683.2 kg m^2/s

Part b)

v' = 8.60 m/s

Part c)

W = 4326.7 J

Explanation:

Part a)

As we know that there is no external torque on the system of two twins

so here we will use

L = mv r + mvr

L = 2(78 \times 4.30 \times 4)

L = 2683.2 kg m^2/s

Part b)

Since angular momentum is conserved here as there is no external torque

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v' = 2v

v' = 8.60 m/s

Part c)

Work done by both of them = change in kinetic energy

so we have

W = 2(\frac{1}{2}mv'^2 - \frac{1}{2}mv^2)

W = m(v'^2 - v^2)

W = 78(8.60^2 - 4.3^2)

W = 4326.7 J

5 0
3 years ago
To calculate work done on an object, _____. A. multiply the force in the direction of motion by the distance the object moved B.
o-na [289]
I believe your answer would be B, hope it helps

6 0
3 years ago
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Why are peer reviews important
Gre4nikov [31]

Answer: So they can find your mistakes that you made you skipped over

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