1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irga5000 [103]
3 years ago
10

Lance Armstrong bikes at a constant speed up the Col d’Izoard, a famous mountain pass. Assume his teammates do such a good job r

iding ahead of him that he can draft behind them and encounter no air resistance. This climb is described as "beyond classification" in terms of its difficulty. The climb is 14.1 km long at a 7.3º average grade. Assume that the combined mass of Lance and his bicycle is 83 kilograms. What is the magnitude of the work he does against the force of gravity? show work
Physics
1 answer:
svetoff [14.1K]3 years ago
7 0

Work done against gravity to climb upwards is always stored in the form of gravitational potential energy

so we can say

W = mgh

here h = vertical height raised

so here we know that

h = 14.1 sin7.3 km

here we have

h = 1.79 km

now from above equation

W = (83 kg)(9.81 m/s^2)(1.79 \times 10^3 m)

W = 1.46 \times 10^6 J

so work done will be given by above value

You might be interested in
Ice of mass 5 g at 0 °C melts to water at 0 °C.
amid [387]

Answer:

Q=1670J

Explanation:

Mass of ice: m=5g=0.005kg

Latent heat: lambda=3.34×10⁵J/kg

Heat received by ice: Q=m×lambda

Q=0.005×3.34×10⁵=5×334=1670J

5 0
3 years ago
What was the result of the Mexican army's victory over the Texan garrison at the Alamo?
sasho [114]

The result of the Mexican victory was that fallen defenders became heroes to the cause of Texan independence.<span> The Battle of the Alamo took place between February 23 and March 6, 1836 and became the central episode of the Texas Revolution . After this thirteen-day battle, the Mexican troops of General President Antonio Lopez de Santa Anna began an attack on San Antonio de Bexar, the current San Antonio in Texas. The Battle of the Alamo fought the army of Mexico against a group of Texan rebels, mostly American settlers. More than four thousand men from Santa Ana stood in front of the Alamo Fort , the last stronghold of the rebels, which barely reached 187. The Alamo was not a fortress prepared to withstand a siege. It is believed that all the rebels of the Alamo died in the siege, but Santa Anna came to lose up to about 900 men during the days that lasted the fight. However, the worst result for Santa Ana was precisely the resistance that the Texan rebels had in the Alamo, which fostered the fighting spirit of the Texans. A few days later, on March 14, 1836, Texas became independent from Mexico and a month later, Santa Ana was imprisoned.</span>

3 0
2 years ago
Read 2 more answers
Which is NOT one of the four principals of Dalton’s atomic theory?
Gre4nikov [31]

Answer:

Your answer would be letter <em><u>B</u></em><em><u>.</u></em><em><u> </u></em><em><u>Electrons</u></em><em><u> </u></em><em><u>orbit</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>nucleus</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>energy</u></em><em><u> </u></em><em><u>level</u></em><em><u>.</u></em>

Explanation:

Hope it helps..

Just correct me if I'm wrong, okay?

But ur welcome!!

(;ŏ﹏ŏ)(◕ᴗ◕✿)

8 0
2 years ago
Read 2 more answers
Kbhgyugybhhv vihiklmb
Ahat [919]

Answer:

?

Explanation:

Can u explain your question?

4 0
2 years ago
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes the
yaroslaw [1]

Answer:

 K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

          p₀ = 0

final moment

          p_f = m_a v_a + m_b v_b

          p₀ = p_f

          0 = m_a v_a + m_b v_b

tells us that

          m_a = 8 m_b

         

           0 = 8 m_b v_a + m_b v_b

           v_b = - 8 v_a                    (1)

indicate that the transfer is complete, therefore the kinematic energy is conserved

starting point

           Em₀ = K₀ = 73 J

final point. After separating the body

          Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²

           K₀ = K_f

           73 = ½ m_a (v_a² + v_b² / 8)

           

we substitute equation 1

           73 = ½ m_a (v_a² + 8² v_a² / 8)

           73 = ½ m_a (9 v_a²)

           73/9 = ½ m_a (v_a²) = K_a

            K_a = 8,111 J

3 0
3 years ago
Other questions:
  • a cart is loaded with a brick and pulled up at a constant speed along an inclined plane to the height of a seattop. if the mass
    9·2 answers
  • How many layers of smooth muscle help with churning food in the stomach? a. one b. two c. three d. four
    7·2 answers
  • What's the hikers average velocity during part D of the hike?
    7·1 answer
  • PLEASE ANSWER QUICK!! A student pushes a wagon full of bricks with a constant force across the ground. Which of
    9·1 answer
  • State two uses of total internal reflection​
    13·1 answer
  • In the experiment, a meter is hooked up to a speaker to monitor the amplitude of the received sound. Suppose the background sign
    5·1 answer
  • A spring toy jumps up from the floor and comes back down to the floor. Its initial speed is 12 m/s. What is the
    8·1 answer
  • The tallest volcano on Mars
    7·2 answers
  • An aeroplane cruises at normal speed. Upon fl ying into turbulent (unstable) air, it suddenly drops downwards vertically. Passen
    11·1 answer
  • In which phase is the substance when its temperature is 250 degrees Celsius?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!