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3 years ago

T or F... All objects with mass (including you) warp space-time. * True False

Physics

2 answers:

lbvjy [14]3 years ago

7 0

Answer:

Explanation:

riadik2000 [5.3K]3 years ago

4 0

False because it’s is false

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You place a large pebble in a slingshot, pull the elastic band back to your chin, and release it, launching the pebble horizonta

sladkih [1.3K]

Answer:

The larger pebble has 25 times more mass.

Explanation:

To solve the exercise it is necessary to apply the work and energy conservation equations.

For the case described, the work done must be preserved and must be the same, that is,

$W = 0$

By definition work linked to the conservation of kinetic energy would be given by

$\Delta KE = W = 0$

$\Delta KE = 0$

$KE_{larger}-KE_{smaller} = 0$

$KE_{larger}=KE_{smaller}$

$\frac{1}{2}m_lv_l^2 = \frac{1}{2}m_sv_s^2$

$m_lv_l^2 = m_sv_s^2$

The ratio between the mass and the velocity would be,

$\frac{m_l}{m_s}=\frac{v_s^2}{v_l^2}$

$\frac{m_l}{m_s} = \frac{500^2}{100^2}$

$\frac{m_l}{m_s} = 25$

Therefore the answer is: The larger pebble has 25 times more mass.

4 0

3 years ago

50 points!!! Kinetics

iris [78.8K]

Answer:

98 m √

Explanation:

How about s = Vo * t + ½at² ?

s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6

and

h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490

Subtract 2nd from first:

0 = -8Vo + 470.4

Vo = 58.8 m/s

h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m

3 0

3 years ago

Read 2 more answers

3) What is the weight of an object with a mass of 5.2 kilograms?

inna [77]

Answer:

50.96 N

Explanation:

weight = mass x gravity

We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.

w = m x g

w = 5.2 kg x 9.8 m/s^2

w = 50.96 N

The weight of the object is 50.96 N (newtons). Hope this helps, thank you !!

8 0

3 years ago

Need some help please

11Alexandr11 [23.1K]

Answer:

$x^2\neq -\frac{5}{13}$

First option

Explanation:

<u>Operations with functions </u>

Given two functions f, g, we can perform a number of operations with them including addition, subtraction, product, division, composition, and many others .

We have

$f(x)=20x^3-7x^2+3x-7$

$g(x)=-13x^2-5$

We are required to find

$\displaystyle \frac{f}{g}(x)$

We simply divide f by g as follows

$\displaystyle \frac{f}{g}(x)=\frac{20x^3-7x^2+3x-7}{-13x^2-5}$

We know rational functions may have problems if the denominator can be zero for some values of x. We must find out if there are such values and exclude them from the domain of the new-found function. We must ensure

$-13x^2-5\neq 0$

or equivalently

$x^2\neq -\frac{5}{13}$

Thus the first option is correct

Note: Since $x^2$ is always a positive number (for x real), our function does not really have any restriction in its domain

8 0

3 years ago

What makes up a nucleus of an atom

Tanzania [10]

The nucleus is the center of an atom.

6 0

4 years ago