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3 years ago

T or F... All objects with mass (including you) warp space-time. * True False

Physics

2 answers:

lbvjy [14]3 years ago

7 0

Answer:

Explanation:

riadik2000 [5.3K]3 years ago

4 0

False because it’s is false

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A 3.10-mm-long, 430 kgkg steel beam extends horizontally from the point where it has been bolted to the framework of a new build

Alex17521 [72]

Answer:

Explanation:

Given that,

The length of the beam L = 3.10m

The mass of the steam beam $m_1$ = 430kg

The mass of worker $m_2$ = 69.0kg

The distance from the fixed point to centre of gravity of beam = $\frac{L}{2}$

and our length of beam is 3.10m

so the distance from the fixed point to centre of gravity of beam is

$\frac{3.10}{2}=1.55m$

Then the net torque is

$=-W_sL'-W_wL\\\\=-(W_sL'+W_wL)$

$W_s$ is the weight of steel rod

$=430\times9.8=4214N$

$W_w$ is the weight of the worker

$=69\times9.8\\\\=676.2N$

Torque can now be calculated

$-(4214\times1.55+676.2\times3.9)Nm\\\\-(6531.7+2637.18)Nm\\\\-(9168.88)Nm$

≅ 9169Nm

<h3>Therefore,the magnitude of the torque is 9169Nm</h3>

4 0

4 years ago

Zeb was moving his dresser. He pushed with 1000N and the resulting acceleration was 200m/s2. What was its mass?

PilotLPTM [1.2K]

Answer:

Explanation:

Formula for Mass (for this question)

$mass=\frac{Force}{Acceleration}$

mass= 1000N/200 $m^{2}$ =5

(pls do correct me if I have any mistakes it would rlly help others!)

7 0

2 years ago

(1 point) A frictionless spring with a 6-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 50 new

guapka [62]

Answer:

x(t) = 0.077cos(6.455t)

Explanation:

If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:

k = 50 / 0.2 = 250 N/m

The equation of simple harmonic motion is as the following:

$x(t) = Acos(\omega t - \phi)$

where $\omega = \sqrt{k/m} = \sqrt{250 / 6} = 6.455$

We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:

$v_{max} = A\omega$

$A = v_{max}/\omega = 0.5 / 6.455 = 0.077 m$

$\phi = 0$ is the initial phase

Therefore, the position of the mass after t seconds is

x(t) = 0.077cos(6.455t)

6 0

3 years ago

When do you produce more pressure on the ground...standing or laying down?

ycow [4]

When you are Standing you produce more pressure on the ground

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3 years ago

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lara31 [8.8K]

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3 years ago