1.16 moles/liter The equation for freezing point depression in an ideal solution is Î”TF = KF * b * i where Î”TF = depression in freezing point, defined as TF (pure) â’ TF (solution). So in this case Î”TF = 2.15 KF = cryoscopic constant of the solvent (given as 1.86 âc/m) b = molality of solute i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1. Solving for b, we get Î”TF = KF * b * i Î”TF/KF = b * i Î”TF/(KF*i) = b And substuting known values. Î”TF/(KF*i) = b 2.15âc/(1.86âc/m * 1) = b 2.15/(1.86 1/m) = b 1.155913978 m = b So the molarity of the solution is 1.16 moles/liter to 3 significant figures.

7 0

3 years ago

Mention the various ways by which soluble and insoluble salts are prepared

LUCKY_DIMON [66]

Answer:

Explanation:

soluble and insoluble salts are prepared by processes like neutralization reactions, simple displacement reactions and double displacement reactions.

4 0

3 years ago

Calculate the pH for the following solutions and indicate whether each solution is acidic or basic.

Nadya [2.5K]

The answer would for sure be 178 because acid & base make that amount so yea!! I’m talllyyy right

6 0

2 years ago

Read 2 more answers

If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?

Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 412.072 \ g \ Cl_2$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂

5 0

3 years ago