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Ira Lisetskai [31]
3 years ago
11

What is the density of 19.2 g of oak that has a volume of 25.7 cm3?

Chemistry
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Density = Mass/Volume

19.2/25.7

= 0.747 or 0.75

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The image shows sedimentary rock layers with index fossils and a fault.
GrogVix [38]

Answer:

Layer 2 and layer 9 is the same relative age since it is the same type of rock and has the same fossils.

Hope this helped!

4 0
3 years ago
How should the enthalpy of an intermediate step be manipulated when used to produce an overall chemical equation?
White raven [17]
The enthalpy of an intermediate step should be manipulated when used to produce an overall equation by using the Hess's law. You could multiply the enthalpy by -1 if this equation is reversed in theory.
8 0
3 years ago
Hydrogen iodide decomposes according to the equation: 2HI(g) H 2(g) + I 2(g), K c = 0.0156 at 400ºC A 0.660 mol sample of HI was
Ira Lisetskai [31]

Answer:

[HI] = 0.264M

Explanation:

Based on the equilibrium:

2HI(g) ⇄ H₂(g) + I₂(g)

It is possible to define Kc of the reaction as the ratio between concentration of products and reactants using coefficients of each compound, thus:

<em>Kc = 0.0156 = [H₂] [I₂] / [HI]²</em>

<em />

As initial concentration of HI is 0.660mol / 2.00L = <em>0.330M, </em>the equlibrium concentrations will be:

[HI] = 0.330M - 2X

[H₂] = X

[I₂] = X

<em>Where X is reaction coefficient.</em>

<em />

Replacing in Kc:

0.0156 = [X] [X] / [0.330M - 2X]²

0.0156 = X² / [0.1089 - 1.32X + 4X² ]

0.00169884 - 0.020592 X + 0.0624 X² = X²

0.00169884 - 0.020592 X - 0.9376 X² = 0

Solving for X:

X = - 0.055 → False solution, there is no negative concentrations

X = 0.0330 → Right solution.

Replacing in HI formula:

[HI] = 0.330M - 2×0.033M

<h3>[HI] = 0.264M</h3>

7 0
3 years ago
Which of the following statements is not correct?
velikii [3]
To answer the question above, multiply the given number of moles by the molar masses.

(A)     (0.20 mole) x (32 g / 1 mole) = 6.4 grams O2
(B)     (0.75 mole) x (62 g / 1 mole) = 46.5 grams H2CO3
(C)     (3.42 moles) x (28 g / 1 mole) = 95.7 grams CO
(D)     (4.1 moles) x (29.88 g / 1 mole) = 122.508 g Li2O

The answer to the question above is letter D.
4 0
3 years ago
"A group of college students believes that herbal tea has remarkable restorative powers. To test their belief, they visit a loca
Georgia [21]

D) the college students

Explanation:

In the experiment conducted by staffs of the nursing home, the group of college students that came for the experiment are the subjects of the experiment. A subject is a person that participates in a research.

  • In this research, the college students are the human participants in the experiment.
  • There must be a mutual agreement between the researcher and the subject because the subject is one that is being tested to see an outcome.
  • A subject can quit a research if he/she deems it fit at any time.

Learn more:

Experiments brainly.com/question/5096428

#learnwithBrainly

7 0
3 years ago
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