Answer:
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Answer:
Takeru bought 72 eggs and baked 18 soufflés .
Step-by-step explanation:
Let
e = number of eggs Takeru bought.
s = number of soufflés Takeru bought.
Then we know that Takeru bought 4 times as many eggs as he baked soufflés, therefore:

And since for every soufflés Takeru bakes he uses 3 eggs, and after backing he has 18 eggs left, we have:
<em>This says that from
eggs there are 18 eggs left after Tkeru used three eggs for each soufflé.</em>
Now we have two equations:


We put the value of e from equation (1) into equation (2) and solve for s and get:


Thus
Number of eggs Takeru bought = 72.
Number of soufflés Takeru bought = 18.
Answer:
The first one would be m^30n^20p^30
And the second one would be a^2 / d^4
Step-by-step explanation:
For 1, you have to multiply the inner exponents by the outer one so you get (m^12n^8) times (m^18n^12p^30). Then you mutiply the two together, so you add the exponents, where you get m^30n^20p^30.
For 2, since you're dividing, you have to subtract the exponents so you get a^2d^-4, but since you shouldn't have the negative you turn it into a^2 / d^4
Hope this helps :)
3x+2(4x-4)=3 - remove parentheses
3x+ 8x-8=3 - collect like terms
11x- 8 =3 - move the constant to the right
11x=3+8 - calculate
11x = 11 - divide both sides by 11
x= 1
Answer: 1.=336m
2.=276.4ft
3.=889in
4.=2.58mi
5.= 4042mm
Step-by-step explanation: