The figure is NOT unique.
Imagine the following quadrilaterals:
Rectangle
Square
We know that:
Both quadrilaterals have at least two right angles.
However, they are not unique because they depend on the lengths of their sides.
Answer:
The figure described is not unique.
Answer:
10 SENIORS
Step-by-step explanation:
x=# of seniors
y=# of juniors
x+y=23, x=2y-7
- plug the value of x in the second equation into the first
- (2y-7)+y=23
- Remove parentheses
- 2y-7+y=23
- Combine like terms
- 3y-7=23
- Add 7 to BOTH sides
- 3y=30
- divide BOTH sides by 3
- 3y/3=30/3
- y=10
- There are 10 juniors in the class
- FINAL STEPS
- Plug y (which is 10) into the first equation
- x+y=23
- x+10=23
- subtract 10 from BOTH sides
- x=13
- Since X equals the number of seniors, there are 10 seniors in the class
Answer:
D. |C -305,000| ≤ 80,000
Step-by-step explanation:
Such an equation will say that the difference from the average of these values is at most half of their difference.
| C -(225000+385000)/2 | ≤ (385000 -225000)/2
|C -305,000| ≤ 80,000 . . . . . matches choice D
♡Let's solve this Step-By-Step!♡
♡Here is the question you asked:
4/7y-2= 3/7y+ 3/14
♡<span>Subtract 3/7y from both sides:
</span><span><span><span><span>4/7</span>y</span>−2</span>−<span>3/7y</span></span>=<span><span><span><span>3/7</span>y</span>+<span>3/14</span></span>−<span>3/7y
</span></span><span><span><span>1/7</span>y</span>−2</span>=<span>3/<span>14
</span></span> ♡<span>Add 2 to both sides:
</span><span><span><span><span>1/7</span>y</span>−2</span>+2</span>=<span><span>3/14</span>+2
</span><span><span>1/7</span>y</span>=<span>31/<span>14
</span></span>♡<span>Multiply both sides by 7:
</span><span>7*<span>(<span><span>1/7</span>y</span>)</span></span>=<span>7*<span>(<span>31/14</span><span>)
</span></span></span>
♡Your answer is:
y=<span>31/2
</span>♡I hope this helps!<span>♡</span>
