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barxatty [35]
2 years ago
8

Which of the following statements are true of thermal energy and kinetic

Physics
1 answer:
Elis [28]2 years ago
4 0

Answer:

a

all the molecules or atoms in motion has kinetic energy

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What is most likely to result immediately after a rainforest in Brazil is clear-cut?secondary succession
Salsk061 [2.6K]

Answer:

the immediate destruction of rain forest in brazil is global warming

5 0
3 years ago
Read 2 more answers
If 6000 J of heat is added to 200 gm of water at 25° C. What will be its final<br>temperature?​
Debora [2.8K]

Answer:

T₂ = 305.17 K

Explanation:

Given that,

Heat, Q = 6000 J

Mass, m = 200 gram

Initial temperature, T₁ = 25° C

We need to find its final temperature. Let it is T₂.

We know that,

Q=mc\Delta T

Where

c is the specific heat of water, c = 4.18 J/g°C

So,

6000=200\times 4.18\times (T_2-298)\\\\\dfrac{6000}{200\times 4.18}=(T_2-298)\\\\7.17=(T_2-298)\\\\7.17+298=T_2\\\\T_2=305.17\ K

So, the final temperature is equal to 305.17  K.

3 0
3 years ago
Discuss the difference between renewable and non- renewable fuels with reference to nuclear fuel and biofuel​
KIM [24]

Answer:

Nonrenewable energy resources, like coal, nuclear, oil, and natural gas, are available in limited supplies. Renewable resources are replenished naturally and over relatively short periods of time. The five major renewable energy resources are solar, wind, water (hydro), biomass, and geothermal.

Explanation:

google:)

4 0
3 years ago
The Department of Natural Resources has selected certain species that are on the verge of extinction due to a lack of prey. Thes
insens350 [35]

Answer:

Habitat manipulation

Explanation:

Habitat manipulation, otherwise known as ecological engineering, is a technique of promoting natural enemies within an ecosystem by making thriving conditions more suitable for them.

<em>In this case, thriving conditions for the species (which happens to be predators and hence, natural enemies) were promoted via artificial introduction of food. </em>

5 0
4 years ago
A wheel of radius R = 0.80 m is pulled by a rope looped around a frictionless axle. The total mass of the wheel and axle assembl
iragen [17]

Answer:

\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18

Explanation:

To find the rotational kinetic energy you first calculate the angular acceleration by using the following formula:

\tau=I\alpha\\\\FR=I\alpha\\\\\alpha=\frac{FR}{I}

F: force applied

R: radius of the wheel

I: moment of inertia

\alpha=\frac{(120N)(0.80m)}{26.88kgm^2}=3.57\frac{rad}{s^2}

With this value you calculate the angular velocity:

\omega^2=\omega_o^2+2\alpha \theta\\

you calculate how many radians the wheel run in 5.0m

\theta=\frac{2\pi (0.8m)}{5.0m}=\approx1.00rad

\omega=\sqrt{2(3.57\frac{rad}{s^2})(1.00rad)}=2.67\frac{rad}{s}

Next, you use the formula for the rotational kinetic energy:

K_R=\frac{1}{2}I\omega^2=(26.88)(2.67)^2 J = 188.63J

For the transnational kinetic energy you use the following equation:

W=\Delta K_T  (net work equals the change in the kinetic energy).

By replacing the you obtain:

\Delta K_T=Fd=(120)(5.0)J=600J

Finally, the ratio between translational rotational kinetic energy is:

\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18

hence, translational kinetic energy is three times the rotational kinetic energy.

6 0
3 years ago
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