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barxatty [35]
1 year ago
8

Which of the following statements are true of thermal energy and kinetic

Physics
1 answer:
Elis [28]1 year ago
4 0

Answer:

a

all the molecules or atoms in motion has kinetic energy

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A wave travels at 175 m/s along the x-axis.If the period of the periodic vibrations of the wave is 3.00 milliseconds,then what i
OlgaM077 [116]

Answer:  

<h2>E) 52.5 cm</h2>

Explanation:

Step one:

given data

period T= 3 milliseconds= 0.003

velocity v= 175m/s

wave lenght λ=?

Step two:

we know that f=1/T

the expression relating period and wave lenght is

v=λ/T

λ=v*T

λ=175*0.002

λ=0.525m

to cm= 0.525*100

=52.5cm

The wavelength of the wave is E) 52.5 cm

7 0
2 years ago
What was significant about the discovery of gallium
Kryger [21]
It confirmed medeleeve's hypothesis (prediction) and showed the use of his table
8 0
3 years ago
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When a board with a box on it is slowly tilted to a larger and larger angle, common experience shows that the box will at some p
Savatey [412]

Answer:

c. The coefficient of kinetic friction is less than the coefficient of static friction

Explanation:

When the box finally does break loose. Then the component of the box weight which is parallel to the board weight parallel component, is equal to the \mu_gn.

w_{box}=\mu_gn

For the box to acce;erate thee must be non-zero net force acting on the box parallel to the board. Or we can say,

w_1>f_g\\w_1>\mu_gn

Therefore the force of kinetic friction must be less than the force of static friction. Thus,

\mu_g

3 0
3 years ago
A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60 cm apart. The string is observed to f
Butoxors [25]

<h2>The frequency of driver is 700 Hz</h2>

Explanation:

The frequency of wave in a string is given by the relation

n = \frac{p}{2l} \sqrt{\frac{T}{m} }

here n is the frequency

p is the number of antinodes and l is the length of string .

T is the tension in string and m is the mass per unit length

Thus 420 =\frac{3}{120} \sqrt{\frac{T}{2} }            I

Now if there is 5 antinodes , the value of p = 5

Thus n = \frac{5}{120} \sqrt{\frac{T}{2} }          II

Dividing II by I , we have

n/420 = 5/3

or n = 5/3 x 420 = 700 Hz

3 0
3 years ago
A 4113 N piano is to be pushed up a(n) 3.99 mfrictionless plank that makes an angle of 25.5â—¦with the horizontal.Calculate the
Serhud [2]

Answer:

W = 14.8 kJ

Explanation:

W = F S cos ∅

W = 4113 x 3.99 x cos 25.5

W = 16410.87 x 0.9025 = 14810.8 J or 14.8 kJ

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3 years ago
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