Question

What is the pOH of a 0.0072 M solution of sodium hydroxide? pOH=?

Answer 1

POH of a 0.0072 M=-lg(0.0072) = 2.1426675

Answer 2

Answer : 2.14

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

Given : $NaOH\rightarrow Na^++OH^-$

1 mole of $NaOH$ gives 1 mole of $OH^_$

Thus 0.0072 moles of  $NaOH$ will give= 0.0072 moles of $OH^_$

$pOH=-\log [OH^]$

$pOH=-\log (0.0072)$

$pOH=2.14$

Therefore, the pOH of the basic solution is 2.14.