Ô tô chuyển động trên đường cong có bán kính R = 300(m). Nếu vận tốc ôtô tăng đều từ v1 =
1 answer:
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<h2>Answer:</h2>
4E
<h2>Explanation:</h2>The elastic potential energy of an elastic material (e.g a spring, a wire), is the energy stored when the material is stretched or compressed. It is given by
U = --------------------(i)
Where;
U = potential energy stored
k = spring constant of the material
x = elongation (extension or compression of the material).
<em>From the first statement;</em>
<em>when elongation (x) is 4cm, energy stored (U) is E</em>
<em>Substitute these values into equation (i) as follows;</em>
E =
E = 8k
<em>Make k subject of the formula</em>
k = [measured in J/cm]
<em>From the second statement;</em>
<em>It is stretched by 4cm.</em>
This means that total elongation will be 4cm + 4cm = 8cm.
The potential energy stored will be found by substituting the value of x = 8cm and k = into equation (i) as follows;
U =
U =
U =
Therefore, the potential energy stored will now be 4 times the original one.
The time of flight of the launched particle will be 2v₀ sinθ / g.
<h3>What is kinematics?</h3>The study of motion without considering the mass and the cause of the motion.
A projectile is launched from level ground with an initial speed v₀ at an angle θ with the horizontal. If air resistance is negligible.
Then the time of flight of the launched particle will be given as,
Determine how long it requires the projectile to reach its highest point in order to calculate the flight duration. Just twice as long as the maximum altitude is the travel time.
At maximum height, .
The time to reach maximum height is given as
The time of flight is given as,
Substituting in , then we have
The time of flight of the launched particle will be 2v₀ sinθ / g.
More about the kinematics link is given below.
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