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oksano4ka [1.4K]
3 years ago
5

Due in a few minutes plzzzz help! Will mark brainliest

Physics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

1. 960

2. 16.6666

3. 0.41666666666

4. 10

Explanation:

A*V=W

A*120=50

V=I*R

R being resistance

(I'm not a 100% sure on 2 & 3)

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What is the quantity of heat energy required to convert 10g cube of ice at -30oC to steam at 120oC. also draw a graph of tempera
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The following required data is,

specific heat capacity of ice= 2.1 kJ/kg

specific heat capacity of water= 4.2 kJ/kg

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specific latent heat of fusion=334 kJ/kg

specific latent heat of vapourisation = 2260 kJ/kg

FORMULAS:-

temperature change=mc(T2-T1)

phase transistion = mL,

where, m=mass , c=specific heat capacity ,L = latent heat of fusion or vapourisation ,(T2-T1)= temparature change

Thus the total amount of heat is,

=mc(T4-T3) + mL + mc(T3-T2) + mL + mc(T2-T1)

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=(0.3)(2.1) + (3.34) + (4.2) +  (22.6) + (0.2)(1.996)

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