Answer:
(a) 1.215 x 10^-13 J
(b) n = 7.6 x 10^5
Explanation:
distance, r = 8.3 x 10^-10 m
Force, F = 192.9 x 10^-9 N
Let the charge is q.
(a) According to the Coulomb's law
q = 1.215 x 10^-13 C
(b) Let n number of electrons are missing.
n = 7.6 x 10^5
Explanation:
Work done is given by the product of force and displacement.
Case 1,
1. A boy lifts a 2-newton box 0.8 meters.
W = 2 N × 0.8 m = 1.6 J
2. A boy lifts a 5-newton box 0.8 meters.
W = 5 N × 0.8 m = 4 J
3. A boy lifts a 8-newton box 0.2 meters.
W = 8 N × 0.2 m = 1.6 J
4. A boy lifts a 10-newton box 0.2 meters.
W = 10 N × 0.2 m = 2 J
Out of the four options, in option (2) ''A boy lifts a 5-newton box 0.8 meters'', the work done is 4 J. Hence, the greatest work done is 4 J.
Answer:
Explanation:
Given the simultaneous equation,
3C+4D=5 .............. 1
2C+5D=2 ............... 2
Solving for the value of C and D using substitution method.
From equation 1;
3C = 5-4D
Divide both sides by 3
3C/3 = (5-4D)/3
C = (5-4D)/3 .... 3
From equation 2:
2C+5D=2
5D = 2-2C
Divide both sides by 5;
5D/5 = 2-2C/5
D = (2-2C)/5 ..... 4
Substitute equation 4 into 3;
C = 5-4{(2-2C)/5}/3
C = [5 - (8-8C/5)]/3
C = [25-(8-8C)/5]/3
C = (17+8C)/15
15C = 17+8C
15C-8C = 17
7C = 17
C = 17/7
Substitute C = 17/7 into equation 4 to get the value of D
D = (2-2(17/7))/5
D = (2-34/7)/5
D = 14-34/35
D = -20/35
D = -4/7
<em>Hence the value of C = 17/7, D = -4/7</em>
Answer:
The force is 
Explanation:
From the question we are told that
The first diameter is 
The second diameter is 
Generally the first area is
=> 
=> 
The second area is
For a hydraulic press the pressure at both end must be equal .
Generally pressure is mathematically represented as
=>
=> 
=>
