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lisov135 [29]
3 years ago
14

Which type of forces would be experienced by a sled that is being pulled by a rope (choose 4)

Physics
1 answer:
sukhopar [10]3 years ago
8 0
Friction, wind resistance, gravity, tension force
You might be interested in
The magnitude of the electrostatic force between two identical ions that are separated by a distance of 8.3 × 10-10m is 192.9 ×
iragen [17]

Answer:

(a) 1.215 x 10^-13 J

(b) n = 7.6 x 10^5

Explanation:

distance, r = 8.3 x 10^-10 m

Force, F = 192.9 x 10^-9 N

Let the charge is q.

(a) According to the Coulomb's law

F=\frac{Kq\times q}{r^{2}}

192.9\times10^{-9}=\frac{9\times10^{9}\times q\times q}{\left (8.3\times 10^{-10}  \right )^{2}}

q = 1.215 x 10^-13 C

(b) Let n number of electrons are missing.

n = \frac{q}{e}=\frac{1.215\times10^{-13}}{1.6\times10^{-19}}

n = 7.6 x 10^5

4 0
4 years ago
PLEASE ANSWER FAST In which of the following situations is the greatest amount of work accomplished? 1. A boy lifts a 2-newton b
GuDViN [60]

Explanation:

Work done is given by the product of force and displacement.

Case 1,

1. A boy lifts a 2-newton box 0.8 meters.

W = 2 N × 0.8 m = 1.6 J

2. A boy lifts a 5-newton box 0.8 meters.

W = 5 N × 0.8 m = 4 J

3. A boy lifts a 8-newton box 0.2 meters.

W = 8 N × 0.2 m = 1.6 J

4. A boy lifts a 10-newton box 0.2 meters.

W = 10 N × 0.2 m = 2 J

Out of the four options, in option (2) ''A boy lifts a 5-newton box 0.8 meters'', the work done is 4 J. Hence, the greatest work done is 4 J.

3 0
4 years ago
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
levacccp [35]

Answer:

Explanation:

Given the simultaneous equation,

3C+4D=5  .............. 1

2C+5D=2 ............... 2

Solving for the value of C and D using substitution method.

From equation 1;

3C = 5-4D

Divide both sides by 3

3C/3 =  (5-4D)/3

C = (5-4D)/3 .... 3

From equation 2:

2C+5D=2

5D = 2-2C

Divide both sides by 5;

5D/5 = 2-2C/5

D = (2-2C)/5 ..... 4

Substitute equation 4 into 3;

C = 5-4{(2-2C)/5}/3

C = [5 - (8-8C/5)]/3

C = [25-(8-8C)/5]/3

C = (17+8C)/15

15C = 17+8C

15C-8C = 17

7C = 17

C = 17/7

Substitute C = 17/7 into equation 4 to get the value of D

D = (2-2(17/7))/5

D = (2-34/7)/5

D = 14-34/35

D = -20/35

D = -4/7

<em>Hence the value of C = 17/7, D = -4/7</em>

6 0
4 years ago
A 2.5 kg ball rolls forward at 10.0 m/s. What is the ball's momentum?​
Anuta_ua [19.1K]

Answer:25kgm/s

Explanation:

mass=2.5kg

Velocity=10m/s

Momentum=mass x velocity

Momentum=2.5 x 10

Momentum=25kgm/s

4 0
4 years ago
A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the s
yan [13]

Answer:

The  force is F_1  = 400.8 \  N

Explanation:

From the question we are told that

   The first  diameter is  d_1 =  4.0 \ cm =  0.04 \ m

   The second diameter is  d_2  =  8.0 \ cm  = 0.08 \  m

   

Generally the first area is  

         A_1  =  \pi  * \frac{d^2_1 }{4}

=>      A_1  = 3.142  * \frac{0.04^2}{4}

=>       A_1  =  0.00126 \ m^2

The  second area is  

     A_2 =  \pi  * \frac{d^2_2 }{4}

     A_2  = 3.142  * \frac{0.08^2}{4}

     A_2  =  0.00503 \ m^2

For a hydraulic press the pressure at both end must be equal .

Generally  pressure is mathematically represented as

    P =  \frac{F}{A}

=>  

   \frac{F_1}{A_1 }  =  \frac{F_2}{A_2 }

=>   F_1  =  \frac{1600}{0.00503}  *  0.00126

=>    F_1  = 400.8 \  N

8 0
3 years ago
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