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Oksi-84 [34.3K]
4 years ago
10

A 2.5 kg ball rolls forward at 10.0 m/s. What is the ball's momentum?​

Physics
1 answer:
Anuta_ua [19.1K]4 years ago
4 0

Answer:25kgm/s

Explanation:

mass=2.5kg

Velocity=10m/s

Momentum=mass x velocity

Momentum=2.5 x 10

Momentum=25kgm/s

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A weatherman carried an aneroid barometer from the ground floor to his office atop the Sears Tower in Chicago. On the level grou
Sophie [7]

Answer:

442.36038 m or 1451.31362 ft

Explanation:

P_1 = Initial pressure = 30.15 inHg

P_2 = Final pressure = 28.607 inHg

\rho = Density of air  = 0.075 lb/ft³

1\ lb/ft^3=16.0185\ kg/m^3

1\ in=0.0254\ m

1\ m=3.28084\ ft

Density of mercury = 13560 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Difference in pressure is given by

P_1-P_2=\rho gh\\\Rightarrow h=\frac{P_1-P_2}{\rho g}\\\Rightarrow h=\frac{(30.15-28.607)\times 13560\times 0.0254\times 9.81}{0.075\times 16.0185\times 9.81}\\\Rightarrow h=442.36038\ m\\\Rightarrow h=442.36038\times 3.28084\\\Rightarrow h=1451.31362\ ft

The height of the building is 442.36038 m or 1451.31362 ft

4 0
3 years ago
You are at the top of the Empire State Building on the 102nd floor, which is located 373 m above the ground, when your favorite
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Answer:

1.5 m

Explanation:

H = actual height of the superhero = ?

H₀ = height of the superhero as observed = 1.73 m

v = speed of the superhero = 0.50 c

Using the equation

H = H_{o} \sqrt{1 - \left ( \frac{v}{c} \right )^{2}}

Inserting the values

H = 1.73 \sqrt{1 - \left ( \frac{0.50 c}{c} \right )^{2}}

H = 1.5 m

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3 years ago
As you sit in a chair, in what direction (or directions) do you exert an action force?
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4 years ago
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Select Light for the type of wave, adjust the wavelength so that the light is red, and increase the amplitude of the light to th
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Answer:

here as we increase the distance the intensity will decrease and hence the amplitude of the electric field will decrease and vice-versa

Explanation:

As wee know that the amplitude of the wave will decide the energy of the wave

Here we know that energy density of electromagnetic wave is given as

u = \frac{1}{2}\epsilon_0E_0^2

now we have

\frac{I}{c} = \frac{1}{2}\epsilon_0 E_0^2

so here we can say that intensity of the wave at the given distance from the source is given by formula

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5 0
3 years ago
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