Yes. If a downward force is created, it will be felt at the end of the rope as well.
IF voltage remains constant, then current is
inversely proportional to resistance.
The correct response is "b).", signifying "false" as the choice.
To solve this problem it is necessary to apply the concepts related to the kinematic equations of movement description.
From the definition we know that the speed of a body can be described as a function of gravity and height



Then applying the kinematic equation of displacement, the height can be written as

Re-arrange to find t,



Thus the calculation of the displacement would be subject to



Therefore the required distance must be 0.547m
Vertical force on the box=mg
<span>the component of gravity parallel=mg*SinTheta </span>
<span>the component of gravity normal=mg*CosTheta </span>
<span>frictional force up the plane: mg*cosTheta*mu max, but if it is sitting still, it is equal and opposite to mg*cosTheta (it cannot be greater than this or it would go up the plane).</span>
Answer: The current flowing through the circuit is 0.01A (or 10 mA)
Explanation:
Use Ohm's Law:

Given the values of U=30V and R=3000Ohm:
