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mezya [45]
3 years ago
7

A 0.6 kg ball is initially at rest on a frictionless, horizontal surface. It is struck by a 0.4 kg ball initially moving with a

velocity of 0.25 m/s toward the right along the x-axis. After the collision, the 0.4 kg ball has a velocity of 0.2 m/s at an angle of 36.9° above the x-axis in the first quadrant. What is the magnitude of the velocity of the 0.6 kg ball after the collision?
Physics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

140

Explanation:

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Answer:

graph A

Explanation:

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What was Marie's speed from point A to point B, in miles/minute?
sveticcg [70]

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40m

Explanation:

40m

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A 8.34 × 103-kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is
Mnenie [13.5K]

Answer:

21870.3156 N

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 1.6 m/s²

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-18.2^2}{2\times 162}\\\Rightarrow a=-1.02234\ m/s^2

The acceleration of the craft should be 1.02234 m/s²

F=ma\\\Rightarrow F=8.34\times 10^3\times 1.02234\\\Rightarrow F=8526.3156\ N

Weight of the craft

W=mg\\\Rightarrow W=8.34\times 10^3\times 1.6\\\Rightarrow W=13344\ N

Thrust

F_t=F+W\\\Rightarrow F_t=8526.3156+13344\\\Rightarrow F_t=21870.3156\ N

The thrust needed to reduce the velocity to zero at the instant when the craft touches the lunar surface is 21870.3156 N

3 0
3 years ago
0.75 km expressed in centimeters
disa [49]
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7 0
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