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mezya [45]
3 years ago
7

A 0.6 kg ball is initially at rest on a frictionless, horizontal surface. It is struck by a 0.4 kg ball initially moving with a

velocity of 0.25 m/s toward the right along the x-axis. After the collision, the 0.4 kg ball has a velocity of 0.2 m/s at an angle of 36.9° above the x-axis in the first quadrant. What is the magnitude of the velocity of the 0.6 kg ball after the collision?
Physics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

140

Explanation:

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Charra [1.4K]

Answer:

A title

Explanation:

Because this is middle school.

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3 years ago
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A disk rotates around an axis through its center that is perpendicular to the plane of the disk. The disk has a line drawn on it
natka813 [3]

Answer:

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Explanation:

The rotated angle is given by:

\theta=\omega0*t+1/2*\alpha*t^2

Since this is a quadratic equation it can be solved using:

x=\frac{-b \± \sqrt{b^2-4*a*c}  }{2*a}

Rewriting our equation:

1/2*\alpha*t^2+\omega0*t-\theta=0

t = \frac{\±\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

Since \sqrt{\omega0^2+2*\theta*\alpha} >\omega0 we discard the negative solution.

t = \frac{\sqrt{\omega0^2+2*\theta*\alpha} -\omega0}{\alpha}

8 0
3 years ago
Which term BEST describes energy
mylen [45]

Answer:

batteries- chemical energy

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Explanation:

hope the answer helps u

3 0
2 years ago
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Why is it making me do this
Julli [10]

Answer:

I don't know.

Explanation:

I have no idea what you are referring to.

4 0
1 year ago
A bicyclist is traveling 10 m/s at 30 degrees
AysviL [449]

Explanation:

The momentum is defined as the product between the mass and velocity:

p = m·v

Let's calculate his total momentum:

ptot = 70kg · 10m/s = 700 kg·m/s

Now we know that he's traveling 30 degrees south-east.

The momentum along the y axis will be:

py = p·cos30° = 606 kg·m/s

Along the x-axis:

px = psin30° = 350 kg·m/s

8 0
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