Answer:
B
Explanation:
Heat increase molecular motion
You need to provide a picture or tell us the examples... we can’t see what you see
Answer:
a) (0, -33, 12)
b) area of the triangle : 17.55 units of area
Explanation:
<h2>
a) </h2>
We know that the cross product of linearly independent vectors
and
gives us a nonzero, orthogonal to both, vector. So, if we can find two linearly independent vectors on the plane through the points P, Q, and R, we can use the cross product to obtain the answer to point a.
Luckily for us, we know that vectors
and
are living in the plane through the points P, Q, and R, and are linearly independent.
We know that they are linearly independent, cause to have one, and only one, plane through points P Q and R, this points must be linearly independent (as the dimension of a plane subspace is 3).
If they weren't linearly independent, we will obtain vector zero as the result of the cross product.
So, for our problem:
![\vec{A} = \vec{P} - \vec{Q} \\\\\vec{A} = (1,0,1) - (-2,1,4)\\\\\vec{A} = (1 +2,0-1,1-4)\\\\\vec{A} = (3,-1,-3)](https://tex.z-dn.net/?f=%5Cvec%7BA%7D%20%3D%20%5Cvec%7BP%7D%20-%20%5Cvec%7BQ%7D%20%5C%5C%5C%5C%5Cvec%7BA%7D%20%3D%20%281%2C0%2C1%29%20-%20%28-2%2C1%2C4%29%5C%5C%5C%5C%5Cvec%7BA%7D%20%3D%20%281%20%2B2%2C0-1%2C1-4%29%5C%5C%5C%5C%5Cvec%7BA%7D%20%3D%20%283%2C-1%2C-3%29)
![\vec{B} = \vec{R} - \vec{Q} \\\\\vec{B} = (6,2,7) - (-2,1,4)\\\\\vec{B} = (6 +2,2-1,7-4)\\\\\vec{B} = (8,1,3)](https://tex.z-dn.net/?f=%5Cvec%7BB%7D%20%3D%20%5Cvec%7BR%7D%20-%20%5Cvec%7BQ%7D%20%5C%5C%5C%5C%5Cvec%7BB%7D%20%3D%20%286%2C2%2C7%29%20-%20%28-2%2C1%2C4%29%5C%5C%5C%5C%5Cvec%7BB%7D%20%3D%20%286%20%2B2%2C2-1%2C7-4%29%5C%5C%5C%5C%5Cvec%7BB%7D%20%3D%20%288%2C1%2C3%29)
![\vec{A} \times \vec{B} = (A_y B_z - B_y A_z) \ \hat{i} - ( A_x B_z-B_xA_z) \ \hat{j} + (A_x B_y - B_x A_y ) \ \hat{k}](https://tex.z-dn.net/?f=%5Cvec%7BA%7D%20%5Ctimes%20%20%5Cvec%7BB%7D%20%3D%20%28A_y%20B_z%20-%20B_y%20A_z%29%20%5C%20%20%5Chat%7Bi%7D%20-%20%28%20A_x%20B_z-B_xA_z%29%20%5C%20%5Chat%7Bj%7D%20%2B%20%28A_x%20B_y%20-%20B_x%20A_y%20%29%20%5C%20%5Chat%7Bk%7D)
![\vec{A} \times \vec{B} = ( (-1) * 3 - 1 * (-3) ) \ \hat{i} - ( 3 * 3 - 8 * (-3)) \ \hat{j} + (3 * 1 - 8 * (-1) ) \ \hat{k}](https://tex.z-dn.net/?f=%5Cvec%7BA%7D%20%5Ctimes%20%20%5Cvec%7BB%7D%20%3D%20%28%20%28-1%29%20%2A%203%20-%201%20%2A%20%28-3%29%20%29%20%5C%20%20%5Chat%7Bi%7D%20-%20%28%203%20%2A%203%20-%208%20%2A%20%28-3%29%29%20%5C%20%5Chat%7Bj%7D%20%2B%20%283%20%2A%201%20-%208%20%2A%20%28-1%29%20%29%20%5C%20%5Chat%7Bk%7D)
![\vec{A} \times \vec{B} = ( - 3 + 3 ) \ \hat{i} - ( 9 + 24 ) \ \hat{j} + (3 + 8 ) \ \hat{k}](https://tex.z-dn.net/?f=%5Cvec%7BA%7D%20%5Ctimes%20%20%5Cvec%7BB%7D%20%3D%20%28%20-%203%20%2B%203%20%29%20%5C%20%20%5Chat%7Bi%7D%20-%20%28%209%20%2B%2024%20%29%20%5C%20%5Chat%7Bj%7D%20%2B%20%283%20%2B%208%20%29%20%5C%20%5Chat%7Bk%7D)
![\vec{A} \times \vec{B} = 0 \ \hat{i} - 33 \ \hat{j} + 12 \ \hat{k}](https://tex.z-dn.net/?f=%5Cvec%7BA%7D%20%5Ctimes%20%20%5Cvec%7BB%7D%20%3D%200%20%5C%20%20%5Chat%7Bi%7D%20-%2033%20%5C%20%5Chat%7Bj%7D%20%2B%2012%20%5C%20%5Chat%7Bk%7D)
![\vec{A} \times \vec{B} =(0, -33, 12)](https://tex.z-dn.net/?f=%5Cvec%7BA%7D%20%5Ctimes%20%20%5Cvec%7BB%7D%20%3D%280%2C%20-33%2C%2012%29)
<h2>B)</h2>
We know that
and
are two sides of the triangle, and we also know that we can use the magnitude of the cross product to find the area of the triangle:
![|\vec{A} \times \vec{B} | = 2 * area_{triangle}](https://tex.z-dn.net/?f=%20%7C%5Cvec%7BA%7D%20%5Ctimes%20%20%5Cvec%7BB%7D%20%7C%20%3D%202%20%2A%20area_%7Btriangle%7D)
so:
![\sqrt{(-33)^2 + (12)^2} = 2 * area_{triangle}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28-33%29%5E2%20%2B%20%2812%29%5E2%7D%20%3D%202%20%2A%20area_%7Btriangle%7D)
![\sqrt{1233} = 2 * area_{triangle}](https://tex.z-dn.net/?f=%20%5Csqrt%7B1233%7D%20%3D%202%20%2A%20area_%7Btriangle%7D)
![35.114= 2 * area_{triangle}](https://tex.z-dn.net/?f=%2035.114%3D%202%20%2A%20area_%7Btriangle%7D)
![17.55 \ units \ of \ area = area_{triangle}](https://tex.z-dn.net/?f=%2017.55%20%5C%20units%20%5C%20%20of%20%5C%20area%20%3D%20%20area_%7Btriangle%7D)
Answer:
It decreases.
Explanation:
between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases