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AlekseyPX
3 years ago
13

A student combined equal amounts of two solutions. One solution had a pH of 2 and the other had a pH of 12. Which would most lik

ely be the resulting pH?
A. 1
B. 3
C. 6
D.11
Physics
2 answers:
zalisa [80]3 years ago
6 0
Answer: optio C. 6.

pH measures the acidity of the solutions.

pH 2 is highly acid and pH 12 is highly basic (alkalyne).

You can be sure that the pH of the solution will be intermediate between 2 and 12.

Given that the volumen of the two solutions are equal the pH of the resulting combination cannot be so close to the original solutions. That takes you to eliminate all the options except the option C. 6.

You cannot be sure that the final pH will be 6, because that will depend on the stregths of the two original solutions, that is why the question asks for the most likely resulting pH, and the answer is optio C. 6. 
baherus [9]3 years ago
4 0

Answer:

C

Explanation:

the answer is C

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A solenoid has a radius Rs = 14.0 cm, length L = 3.50 m, and Ns = 6500 turns. The current in the solenoid decreases at the rate
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Answer:

E = 58.7 V/m

Explanation:

As we know that flux linked with the coil is given as

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here we have

A = \pi R_s^2

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now we have

\phi = N(\mu_o N i/L)(\pi R_s^2)

now the induced EMF is rate of change in magnetic flux

EMF = \frac{d\phi}{dt} = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

now for induced electric field in the coil is linked with the EMF as

\int E. dL = EMF

E(2\pi r_c) = \mu_o N^2 \pi R_s^2 \frac{di}{dt}/L

E = \frac{\mu_o N^2 R_s^2 \frac{di}{dt}}{2 r_c L}

E = \frac{(4\pi \times 10^{-7})(6500^2)(0.14^2)(79)}{2(0.20)(3.50)}

E = 58.7 V/m

3 0
3 years ago
A spaceship leaves a space station and emits a flash of light that travels at a speed of 300,000 km/s. The spaceship starts out
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3 years ago
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melamori03 [73]
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A hydrogen atom in the n=7 state decays to the n=4 state. what is the wavelength of the photon that the hydrogen atom emits? use
frez [133]

A hydrogen atom in the n=7 state decays to the n=4 state. The wavelength of the photon that the hydrogen atom emits is 4592.59nm.

The Energy of photon is the energy possessed by a photon when it moves from a high energy level to a low energy level. It emits a photon of a certain wavelength. The following relation can be used to find out the relation between the energy levels and the energy possessed:

E = 13.6 × Z² (1/n₂² - 1/n₁²) eV

where, n₁ is the initial energy level i.e. n₁ =7

            n₂ is the higher energy level i.e. n₂ = 4

            E is the energy possessed

            Z is the atomic number, Z = 1 for H-atom

Subsituting in above equation,

E = 13.6 (1/16 - 1/49) eV

E = 0.27 eV

We know that,

E = hc / λ  

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On subsituting,

0.27 eV = 1240/ λ

⇒ λ = 4592.59 nm

Hence, the wavelength of photon emitted by Hydrogen atom is 4592.59nm.

Learn more about Energy of Photon here, brainly.com/question/2393994

#SPJ4

 

5 0
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