The length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.
<h3 /><h3>A sketch of the uniform stick and the mass</h3>
The sketch of the uniform stick and the mass will be two based on the given statement.
<h3>when the uniform stick balances on knife at 10 cm from one end;</h3>
-------------------------------------------------------
↓ 10cm Δ (L - 10 cm) ↓
200g M
<h3>When the knife edge is moved 5 cm further</h3>
|---------------15 cm-----------------|
-----------------------------------------------------------------------
↓ 8.75 cm Δ (L - 15 cm) ↓
200g M
From the first diagram, apply principle of moment;
200(10) = M(L - 10) ------- (1)
From the second diagram, apply principle of moment;
200(8.75) = M(L - 15) ------- (2)
From equation (1); M = (2000) / (L - 10)
From equation (2); M = (1750) / (L - 15)
Solve (1) and (2);
(2000) / (L - 10) = (1750) / (L - 15)
1750(L - 10) = 2000(L - 15)
L - 10 = 2000/1750(L - 15)
L - 10 = 1.143(L - 15)
L - 10 = 1.143L - 17.14
17.14 - 10 = 1.143L - L
7.14 = 0.143L
L = 7.14/0.143
L = 50 cm
<h3>Mass of the uniform stick</h3>
M = (2000) / (50 - 10)
M = 50 g
Thus, the length of the uniform meter stick is 50 cm and the mass of the uniform meter stick is 50 g.
Learn more about length of meter stick here: brainly.com/question/17225736
#SPJ1
