A)
2revs in 0.08s
so in 1s thats 25revs
therefore thats <u>50π radians</u> in one second
b)
well, ω=2π/T
therefore ω=50π = 157.079rads^-1
and v=rω where r is in meters;
v=0.3x157.079
<u>v=47.123ms^-1</u>
c)
f=1/T
f=1/period for one rotation
1 rotation = 0.08/2 = 0.04
f=1/0.04
<u>f=25Hz</u>
Answer:
The particle speed is constant.
Explanation:
Particles in gases travel quickly in all directions, frequently clashing with each other and the container's edge. The particles gather kinetic energy and travel faster as the temperature rises. The true average speed of the particles is determined by their mass and temperature; larger particles travel more slower around the same temperature than lighter particles.
Thus, the false statement about a wave moving through a constant speed is that:
The particle speed is constant.
Answer:
Vi = 24.14 m/s
Explanation:
If we apply Law of Conservation of Energy or Work-Energy Principle here, we get: (neglecting friction)
Loss in K.E of the Rock = Gain in P.E of the Rock
(1/2)(m)(Vi² - Vf²) = mgh
Vi² - Vf² = 2gh
Vi² = Vf² + 2gh
Vi = √(Vf² + 2gh)
where,
Vi = Rock's Speed as it left the ground = ?
Vf = Final Speed = 17 m/s
g = 9.8 m/s²
h = height of rock = 15 m
Therefore,
Vi = √[(17 m/s)² + 2(9.8 m/s²)(15 m)]
Vi = √583 m²/s²
<u>Vi = 24.14 m/s</u>
<span> delta S. The
change in entropy is a measure of how the reaction will affect the
system's stability. If delta S is negative, the system will become more
stable as it reacts, so it will be spontaneous. Delta H will follow
the same rule. </span>
Answer:
Explanation:
Given
Speed of Primary wave 
Speed of secondary wave 
difference in timing of two waves are 
Suppose both travel a distance of d km then
Subtract (ii) from (i)
![d[\frac{1}{4.5}-\frac{1}{8}]=77.2](https://tex.z-dn.net/?f=d%5B%5Cfrac%7B1%7D%7B4.5%7D-%5Cfrac%7B1%7D%7B8%7D%5D%3D77.2)
![d[0.0972]=77.2](https://tex.z-dn.net/?f=d%5B0.0972%5D%3D77.2)
