Explain sun or friction or fuel or electricity Explain any one of them

Physics

2 answers:

Sphinxa [80]3 years ago

5 0

Answer:

The Sun is a celestial body. It's a massive, spinning orb of heated gas that's glowing. The Sun is similar to the stars that may be seen in the night sky. The Sun is the centre of our Solar System, containing the majority of its mass. The Sun is the centre of our Solar System, and all of the planets, including Earth, revolve around it.

Explanation:

xxMikexx [17]3 years ago

3 0

Answer: hmm, i choose sun.

Explanation: The sun is the center of the solar system. It warms up planets and many other things. The main thing that makes the sun so important is warming US up, the planet earth.

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Shine the flashlight on the liquid crystal sheet. Did you observe evidence that light carries energy?

Artemon [7]

Answer:

no i did not observe anything

Explanation:

6 0

3 years ago

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

xz_007 [3.2K]

Answer:

a) $\Delta{t} = 5.39s$

b) the motorcycle travels 155 m

Explanation:

Let $t_2-t_1 = \Delta{t}$ , then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):

$v_{m2}=v_0+a\Delta{t}\\x+d=(\frac{v_0+v_{m2}}{2} )\Delta{t}\\v_c = v_0 = \frac{x}{\Delta{t}}$

where:

$v_{m2}$ is the speed of the motorcycle at time 2

$v_{c}$ is the velocity of the car (constant)

$v_{0}$ is the velocity of the car and the motorcycle at time 1

d is the distance between the car and the motorcycle at time 1

x is the distance traveled by the car between time 1 and time 2

Solving the system of equations:

$\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]$

$v_0\Delta{t}=\frac{v_0+v_{m2}}{2}\Delta{t}-d \\\frac{v_0+v_{m2}}{2}\Delta{t}-v_0\Delta{t}=d\\(v_0+v_{m2})\Delta{t}-2v_0\Delta{t}=2d\\(v_0+v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\(2v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\a\Delta{t}^2=2d\\\Delta{t}=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*58}{4}}=\sqrt{29}=5.385s$