Answer:
Vo = 4.5 [m/s]
Explanation:
In order to solve this problem, we must use the following equation of kinematics.
where:
Vf = final velocity = 12 [m/s]
Vo = initial velocity [m/s]
a = acceleration = 1.5 [m/s²]
t = time = 5 [s]
Now replacing:
The unit power is actually watt which is true
Answer:8.2N
Explanation:I did the quiz on k12 and that’s the answer i got :)
These sponsorships are somehow related to globalisation, as they are a global phenomenon, but some of them are on a very local scale, so globalisation is not a necessary part in them.
The best answer is c) commercialisation - atheletic competitions are turned into sources of profit, and athletes compete with the thought of winning money through it and the companies hope to increase their revenue by advertising during the sports events
The rocket would have gone 125 m away in deep space.The speed when it has gone 300 m is 76.7 m/s.
Answer:
The distance the rocket traveled is 125 m. The speed when it has gone 300 m is 76.7 m/s.
Explanation:
According to the equations of motion, if an object is moving with constant acceleration, then the distance travelled by the object with that acceleration and within a specific time can be obtained as
Since the initial velocity is given as u = 0 at t = 0. Then at t = 10 s, the acceleration is given by 2.5 m/.
Thus,
s= 0 + (×2.5×)=125 m.
Thus, the rocket would have gone 125 m away in deep space.
Similarly, if it had gone 300 m then its speed can be determined using the third equation of motion.
Since, here v is unknown and u is known as 0 with a = 2.5 m/.
2× 9.8×300=v²
5880=v²
Thus, the speed v =
So, the speed when it has gone 300 m is 76.7 m/s.