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MariettaO [177]
3 years ago
10

Saturn is 890,700,000 miles from the Sun. What is the distance in meters?

Physics
2 answers:
Maslowich3 years ago
6 0

Answer:

1.4936 trillion meters

Explanation:

From an average distance of 886 million miles Saturn is 9.5 astronomical units away from the sun

zmey [24]3 years ago
4 0
I think the answer would be “1.4936 trillion meters”
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What are the density, specific gravity and mass of the air in a room whose dimensions are 4 m * 6 m * 8 m at 100 kPa and 25 C.
Volgvan

Answer:

Density = 1.1839 kg/m³

Mass = 227.3088 kg

Specific Gravity = 0.00118746 kg/m³

Explanation:

Room dimensions are 4 m, 6 m & 8 m. Thus, volume = 4 × 6 × 8 = 192 m³

Now, from tables, density of air at 25°C is 1.1839 kg/m³

Now formula for density is;

ρ = mass(m)/volume(v)

Plugging in the relevant values to give;

1.1839 = m/192

m = 227.3088 kg

Formula for specific gravity of air is;

S.G_air = density of air/density of water

From tables, density of water at 25°C is 997 kg/m³

S.G_air = 1.1839/997 = 0.00118746 kg/m³

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3 years ago
Driving along a crowded freeway, you notice that it takes a time tt to go from one mile marker to the next. When you increase yo
ddd [48]

Answer:

38.6 mi/h

Explanation:

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Let v (mi/s) be your original speed, then the time t it takes to go 1 mi/s is

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Since you increase v by 0.00206 mi/s, your time decreases by 15 s, this means

t - 15 = 1/(v+0.00206)

We can substitute t = 1/v to solve for v

\frac{1}{v} - 15 = \frac{1}{v + 0.00206}

We can multiply both sides of the equation with v(v+0.00206)

v+0.00206 - 15v(v+0.00206) = v

-15v^2 - 0.0308v + 0.00206 = 0

v= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

v= \frac{0.03083\pm \sqrt{(-0.03083)^2 - 4*(-15)*(0.00205)}}{2*(-15)}

v= \frac{0.03083\pm0.35}{-30}

v = -0.01278 or v = 0.01 0724 mi/s

Since v can only be positive we will pick v = 0.010724 mi/s or 0.010724*3600 = 38.6 mi/h

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