How many chiral carbon atoms are present in a molecule of 2,3,4-trichloropentane?

How to calculate the percentage of a anhydrous salt

Anna35 [415]

Yep u right bro but like you know I’m here with these guys you know what I mean tho

8 0

4 years ago

Why is distilled water added to the crucible after igniting the magnesium metal?

Lady_Fox [76]

The reason why distilled water is being added to the crucible after having It to be ignited with the magnesium ribbon is mainly because it is needed to decompose the magnesium nitride to produce a more better result in the experiment and prevent it from reacting more vulgar such as having it to explode.

7 0

3 years ago

Read 2 more answers

If a disease killed all the mice in a food web how would that effect owls

andriy [413]

The owls would have to find an alternate food source and it would be harder for them to survive

7 0

3 years ago

Read 2 more answers

What’s the correct answer

Fed [463]

The correct answer is:
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" F and Br , because they are in the same group" .
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Note:
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Choice [B]: "F and Br ; because they are in the same period" ; is incorrect; since "F" and "Br" are not in the same "period" (that is, "row").
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Choice [C]: "Na and Mg; because they are in the same group {"column"} ; is incorrect; since: "Na" and "Mg are NOT in the same group {"column"].
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Choice [D]: "Na and Mg" ; because they are in the same period {"row"}; is incorrect. Note: "Na" and "Mg" are, in fact, in the same period {"row"}. However, as aforementioned, {Mg and Na} are not in the same group {"column".}.

Note: The similiarities in physical and chemistry properties among elements are determined and organized — or tend to be so—by "groups" {"columns"} — NOT by "periods" {rows}.
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3 0

4 years ago

Enter your answer in the provided box. what is the emf of a cell consisting of a pb2 / pb half-cell and a pt / h / h2 half-cell

sp2606 [1]

Answer:

The emf of the electrochemical cell has been calculated to be <u>3.364.</u>

in order to calculate the emf we need to apply Nernst equation.

The emf has been the potential of the cell in the reaction with the change in the electrons in the reaction. The emf of the cell has been given by the Nernst equation as -

emf= E⁰ cell - 0.059/n. log 1/concentration

Computation for the emf of the cell

The given cell has the number of electrons transfer, n= 2

The concentration of Pb2= 0.57 M

The concentration of H= 0.090 M

The cell potential of the reaction has been= -0.126

Substituting the values for the emf of the cell:

emf= -0.126- 0.059/2 * log 1/ [0.57]x [0.090] ²

emf= 1.555* 2.337

emf=3.634 v

The emf of the electrochemical cell has been calculated to be 3.634 v.

Learn more about emf here-

brainly.com/question/9425530

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4 0

2 years ago