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4 years ago

What is the mass of sodium in 3 moles of sodium chloride

Chemistry

1 answer:

SashulF [63]4 years ago

8 0

4.00 moles of sodium has a mass of 91.96 grams.

To find an element's molar mass, you can use its atomic weight.

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Help would be majorly appreciated

Sophie [7]

Answer:

a) the atomic number is 15

b) the mass number is 15+16 = 31

c) element is phosphorus

d)Group 15 period 3

6 0

3 years ago

Give the volume indicated. Be sure to include all significant figures.

miskamm [114]

Answer: -

Explanation: -

From the diagram, we see that volume goes from 70 to 75 in 5 markings.

Each marking is for 1.

It is the most accuracy possible as there is no smaller marking.

Significant figures expresses the required amount of accuracy.

Thus the volume indicated from the diagram is 71 .

8 0

3 years ago

Read 2 more answers

HELP<br> How can you tell if mass is being conserved

Murljashka [212]

I can help say like gas is steaming from a pot like you cooking on the gas is being conserved after it evaporates and liquid if you drink water it’s going into your body so it’s being conserved and solid said like i have a brick and you throw it and it breaks it had been conserved because it’s broken

8 0

3 years ago

How many moles of HCl are present in 0.70 L of a 0.33 M HCl solution?

tester [92]

Answer:

0.23 mol

Explanation:

3 0

3 years ago

How many moles are in 2.4g of carbon dioxide (CO2)?

miv72 [106K]

Answer:

$\boxed {\boxed {\sf 0.055 \ mol \ CO_2}}$

Explanation:

To convert form grams to moles, the molar mass must be used. This is the mass (in grams) in 1 mole of a substance.

We can use the values on the Periodic Table. First, find the molar masses of the individual elements: carbon and oxygen.

C: 12.011 g/mol
O: 15.999 g/mol

Check for subscripts. The subscript of 2 after O means there are 2 oxygen atoms, so we have to multiply oxygen's molar mass by 2 before adding.

O₂: 2* (15.999 g/mol)=31.998 g/mol
CO₂: 12.011 g/mol + 31.998 g/mol =40.009 g/mol

Use the molar mass as a ratio.

$\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}$

Multiply by the given number of grams.

$2.4 \ g \ CO_2 *\frac {44.009 \ g\ CO_2}{ 1 \ mol \ CO_2}$

Flip the fraction so the grams of carbon dioxide cancel.

$2.4 \ g \ CO_2 *\frac { 1 \ mol \ CO_2}{44.009 \ g\ CO_2}$

$2.4 *\frac { 1 \ mol \ CO_2}{44.009}$

$\frac { 2.4 \ mol \ CO_2}{44.009}= 0.0545342998 \ mol \ CO_2$

The original measurement of grams has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

The ten thousandth place has a 5, so we round the 4 to a 5.

$0.055 \ mol \ CO_2$

2.4 grams of carbon dioxide is about 0.055 moles.

8 0

3 years ago