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gogolik [260]
2 years ago
14

A passenger on a stopped bus notices that rain is falling vertically just outside the window. When the bus moves with constant v

elocity, the passenger observes that the falling raindrops are now making an angle of 18 ∘ with respect to the vertical.1. What is the ratio of the speed of the raindrops to the speed of the bus?2. Find the speed of the raindrops, given that the bus is moving with a speed of 19 {m/s}.
Physics
1 answer:
nekit [7.7K]2 years ago
5 0

Answer:

1)0.325

2)6.17\ \rm m/s

Explanation:

<u>Given:</u>

The angle that falling raindrops make with the vertical=18^\circ

Let V_R be the velocity of the raindrops and V_B be the velocity of the bus.

1)

\dfrac{V_R}{V_B}=\tan 18^\circ\\\dfrac{V_R}{V_B}=0.315\\

2)Speed of the raindrops=0.315\times 19

=6.17\ \rm m/s

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(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 5.00 ✕ 10-5 kg hangs motionless on it.
sertanlavr [38]

a)The tension in the vertical strand will be 0.00049 N.

b))The tension in the horizontal strand will be 0.001284 N.

c)The ratio of tension in the horizontal strand to the tension in the vertical strand will be  2.62.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given data;

Mass of spiderweb = 5.00 ✕ 10⁻⁵ kg

The tension in a horizontal strand of a spiderweb, Tₓ

The tension in a  vertical strand of a spiderweb, Tₐ

The angle at which the strand sags, Θ = 10.0°

R is the ratio of  tension in the horizontal strand to the tension in the vertical strand

a)

From the FBD,

The tension  in the vertical strand is equal to the weight of the spider;

Tₐ = W

Tₐ = mg

Tₐ= 5 x 10⁻⁵ kg x 9.8 m / s²

Tₐ= 0.00049 N.

(b)

The super's total vertical forces are zero since it is not moving the value of the tension in the horizontal strand;

Tₓ = mg/( 2sinΘ)

Tₓ = 5 x 10⁻⁵ kg x 9.8 m /s² / ( 2 sin 11° )

Tₓ= 0.001284 N.

c)

R is the tension in the vertical strand divided by the tension in the horizontal strand.

R= Tₐ / Tₓ

R= 0.001284 N / 0.00049 N

R= 2.62

Hence, the tension in a vertical strand of a spiderweb, the tension in a horizontal strand of a spiderweb, and the ratio of tension in the horizontal strand to the tension in the vertical strand will be 0.00049 N, 0.001284 N, and 2.62 respectively.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

#SPJ1

6 0
2 years ago
Need help with this<br> THANKS TO WHO HELPS &lt;3
nekit [7.7K]

Answer:

because it's north

Explanation:

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8 0
2 years ago
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A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction be
SVEN [57.7K]
The horizontal force : f = k*N
k- coefficient of friction
k = f /N
N = m * g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057
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2 years ago
An object travels 20 m in 10s What is its speed?
ella [17]

speed=distance/time

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time=10s

speed=?

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In the diagnostic radiology energy range (which includes mammography) from 23 to 150 kVp, which of the following tissues possess
Semmy [17]

Answer:

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