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gogolik [260]
2 years ago
14

A passenger on a stopped bus notices that rain is falling vertically just outside the window. When the bus moves with constant v

elocity, the passenger observes that the falling raindrops are now making an angle of 18 ∘ with respect to the vertical.1. What is the ratio of the speed of the raindrops to the speed of the bus?2. Find the speed of the raindrops, given that the bus is moving with a speed of 19 {m/s}.
Physics
1 answer:
nekit [7.7K]2 years ago
5 0

Answer:

1)0.325

2)6.17\ \rm m/s

Explanation:

<u>Given:</u>

The angle that falling raindrops make with the vertical=18^\circ

Let V_R be the velocity of the raindrops and V_B be the velocity of the bus.

1)

\dfrac{V_R}{V_B}=\tan 18^\circ\\\dfrac{V_R}{V_B}=0.315\\

2)Speed of the raindrops=0.315\times 19

=6.17\ \rm m/s

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Explanation:

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Now, if we assume C_{D}, \rho and A_{D} do not change, we can rewrite (1) as:

F_{D}=C.V^{2} (2)

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So, if we have a new velocity V_{n} , which is the double of the former velocity:

V_{n}=2V (3)

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F_{D}=C.V_{n}^{2}=C.(2V)^{2}

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A billiard ball of mass m moving with speed v1=1 m/s collides head-on with a second ball of mass 2m which is at rest. What is th
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Explanation:

From the question w are told that

     The mass of the billiard ball A is =m

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    The initial speed  of the billiard ball  B = 0

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                 \frac{1}{2} m (v_1)^2 + \frac{1}{2} 2m (0) ^ 2 = \frac{1}{2} m (v_A)^2 + \frac{1}{2} 2m (v_B)^2

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Multiplying through by \frac{1}{2}m

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