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3 years ago

Why does cold water sink?

Physics

2 answers:

seraphim [82]3 years ago

8 0

It’s because warm air is less dense

KATRIN_1 [288]3 years ago

6 0

Because Any object or substance that is less dense than a fluid will float in that fluid, so hot water rises (floats) in colder water. When fluids are cooled, they contract and therefore become more dense. Any object or substance that is more dense than a fluid will sink in that fluid, so cold water sinks in warmer water

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THE LENGTH OF A PENDULUM IS (1.5±0.01)m AND THE ACCELERATION DUE TO GRAVITY IS TAKEN AS (9.8±0.1)ms-² calculate the time period

tiny-mole [99]

Answer:

2.4583 ± 0.0207 seconds

Explanation:

The time period of a pendulum is approximately given by the formula ...

T = 2π√(L/g)

The maximum period will be achieved when length is longest and gravity is smallest:

Tmax = 2π√(1.51/9.7) ≈ 2.47903 . . . seconds

The minimum period will be achieved for the opposite conditions: minimum length and maximum gravity:

Tmin = 2π√(1.49/9.9) ≈ 2.43756 . . . seconds

If we want to express the uncertainty using a symmetrical range, we need to find half their sum and half their difference.

T = (2.47903 +2.43756)/2 ± (2.47903 -2.43756)/2

T ≈ 2.4583 ± 0.0207 . . . seconds

We have about 2+ significant digits in the given parameters, so the time might be rounded to 2.46±0.02 seconds.

5 0

3 years ago

Two point charges are placed on the x axis.The firstcharge, q1= 8.00 nC, is placed a distance 16.0 mfromthe origin along the pos

deff fn [24]

Answer:

E = (0, 0.299) N

Explanation:

Given,

Charge $q_1\ =\ 8.0\ nC$
Charge $q_2\ =\ 6.0\ nC$
Distance of the first charge from the origin = (16m, 0)
Distance of the second charge from the origin = (-9, 0)
Point where the electric field required = (0, 12m)

Let $\theta_1\ and\ theta_2$ be the angle of the electric fields by first and second charge at the point A.

$\therefore sin\theta_1\ =\ \dfrac{12}{20}\\\Rightarrow \theta_1\ =\ sin^{-1}\left (\dfrac{12}{20}\ \right )\\\Rightarrow \theta_1\ =\ 36.87^o\\\\\therefore sin\theta_1\ =\ \dfrac{12}{9}\\\Rightarrow \theta_1\ =\ sin^{-1}\left (\dfrac{12}{9}\ \right )\\\Rightarrow \theta_1\ =\ 53.13^o\\$

Electric field by charge $q_1$ at point A,

$F_1\ =\ \dfrac{kq_1}{r_1^2}\\\Rightarrow F_1\ =\ \dfrac{9\times 10^9\times 8\times 10^{-9}}{20^2}\\\Rightarrow F_1\ =\ 0.18\ N/C$

Electric field by the charge $q_2$ at point A,

$F_1\ =\ \dfrac{kq_1}{r_1^2}\\\Rightarrow F_1\ =\ \dfrac{9\times 10^9\times 6.0\times 10^{-9}}{16^2}\\\Rightarrow F_1\ =\ 0.24\ N/C$

Now,

Net electric field in horizontal direction at point A $F_x\ =\ F_{1x}\ +\ F_{2x}\\\Rightarrow F_x\ =\ F_1cos\theta_1\ +\ F_2cos\theta_2\\\Rightarrow F_x\ =\ 0.18\times( -cos36.87^o)\ +\ 0.24\times cos53.13^o\\\Rightarrow F_x\ =\ -0.144\ +\ 0.144\ N/C\\\Rightarrow F_x\ =\ 0\ N/C$

Net electric field in vertical direction at point A.

$F_y\ =\ F_{1y}\ +\ F_{2y}\\\Rightarrow F_y\ =\ F_1sin\theta_1\ +\ F_2sin\theta_2\\\Rightarrow F_y\ =\ 0.18\times sin36.87^o\ +\ 0.24\times sin53.13^o\\\Rightarrow F_y\ =\ 0.180\ +\ 0.192\\\Rightarrow F_y\ =\ 0.299\ N/C$

Hence, the net electric field at point A,

$F\ =\ ( 0, 0.299 )\ N/C.$

5 0

3 years ago

Grade 11 Physics

xeze [42]

1. Displacement = 50 m North. Distance = 150m
Displacement is a vector. Distance is a scalar.

2. Displacement is 100 miles East.

6 0

3 years ago

Unos amigos de 5 integrantes salen a comer, el primero pide un pollo a la brasa que cuesta S/50.00, el segundo un aeropuerto que

ser-zykov [4K]

Respuesta:

$138.39

Explicación:

Paso 1: Calcular el total que gastaron

El total que gastaron es igual a la suma de los que gastó cada uno.

$50.00 + $28.50 + $20.50 + $10.80 + $22.00 = $131.80

Paso 2: Calcular el 5% de $131.80

$131.80 × 5% = $6.59

Paso 3: Calcular el total que pagó con la tarjeta

A los $131.80 que gastaron debe sumarle los $6.59 por el uso de tarjeta.

$131.80 + $6.59 = $138.39

3 0

2 years ago

Double a keeping b and x constant

hram777 [196]

Try and multiply A only and leave B and X alone (constant) try a number like 2

7 0

3 years ago