let's take a peek at the graph, it has the points of (-5 , 3) and (-2 , -3), so then
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[-2-(-5)]^2+[-3-3]^2}\implies d=\sqrt{(-2+5)^2+(-3-3)^2} \\\\\\ d=\sqrt{3^2+(-6)^2}\implies d=\sqrt{45}\implies d\approx 6.71](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-5%7D~%2C~%5Cstackrel%7By_1%7D%7B3%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-2%7D~%2C~%5Cstackrel%7By_2%7D%7B-3%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B%5B-2-%28-5%29%5D%5E2%2B%5B-3-3%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%28-2%2B5%29%5E2%2B%28-3-3%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%3D%5Csqrt%7B3%5E2%2B%28-6%29%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B45%7D%5Cimplies%20d%5Capprox%206.71)
Answer:
C
Step-by-step explanation:
Answer:
same
Step-by-step explanation:
Answer: 1
Step-by-step explanation:
The nearest whole number would be 1, because the fraction 5/8 to a decimal is 0.625.
Answer:
v= 6km/h - 1km/h^2 * t
Step-by-step explanation:
From the information, it seems the runner is slowing down because the speed at 1st hour is 5km/h but at 3rd hour becomes 3km/h.
If v= velocity, v0= initial speed, t= time, and the a=acceleration then the function would be:
v= v0 + a * t
To find the acceleration you need to do this equation:
acceleration= velocity1- velocity3 / t3-t1
a = (3km/h-5km/h)/ (3 hour- 1 hour)
a = (-2km/h)/2hour= -1 km/hour^2
After that, you need to find the initial speed. Try to put the 1st-hour variable into the full equation. It would look like this
v= v0 + a * t
5km/h= v0 + (-1 km/hour^2 * 1 hour)
v0= 5km/h + 1km/h
v0= 6km/h
Then the full function would be:
v= 6km/h - 1km/h^2 * t
The graph would look like a backslash(\) from 5 gradually go down to 1.
6
5 O
4 O
3 O
2 O
1 O
1 2 3 4 5
