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galben [10]
3 years ago
14

The actual mechanical advantage of any machine is its__________divided by its________________

Physics
1 answer:
zaharov [31]3 years ago
4 0

Answer: Load divided by it effort

Explanation:

Mechanical advantage of any machine is its load divided by its effort

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Calculate ideal work (in J) when a single stream of 1 mole of air is heated and expanded from 25 C and 1 bar to 100 C and 0.5 ba
NISA [10]

Answer:

-1786.5J

Explanation:

Temperature 1=T1=25°c

Temperature 2=T2=200°c

Pressure P1=1bar

Pressure P2=0.5bars

T=37°c+273=310k

Note number if moles=1

Recall work done =2.3026RTlogp2/P1

2.3026*8.314*310log(0.5/1)

-1786.5J

7 0
3 years ago
3. The electric field of a sinusoidal electromagnetic wave has an amplitude of 5.0 V/m. How much radiation energy passes through
True [87]

Answer:

e) 179 J

Explanation:

E_{o} = Magnitude of electric field = 5 V/m

A = Area of window = 1.5 m²

c = speed of electromagnetic wave = 3 x 10⁸ m/s

\Delta t = time interval = 1 h = 3600 sec

radiation energy is given as

U = (0.5)\epsilon _{o}E_{o}^{2}cA\Delta t

U = (0.5)(8.85\times 10^{-12})(5)^{2}(3\times 10^{8})(1.5)(3600)

U = 179 J

6 0
2 years ago
A 4.00-kg particle moves along the x axis. Its position varies with time according to x 5 t 1 2.0t 3, where x is in meters and t
White raven [17]

Answer:

Explanation:

Given equation is ,

x =t + 2 t³ ,

dx/dt = velocity ( v ) = 1 + 6 t²

a) kinetic energy = 1/2 m v² = .5 x 4 ( 1 + 6 t² )² = 2 ( 1 + 6 t²)²

b ) Acceleration = dv /dt = 12 t .

force( F ) = mass x acceleration = 4 x 12 t = 48 t

Power = force x velocity = 48 t x ( 1 + 6 t²). = 48 t + 288 t³ )

work done = ∫ F dx =∫ 48 t x( 1 + 6t² )dt ; =  [48t²/2 + 48 x 6 x t³ /3 = 24 t² + 96 t³ )]₀² =  864 J

6 0
3 years ago
Read 2 more answers
A force of 50 newtons causes a sled to accelerate at a rate of 5 meters per second. What is the mass of the sled.
notka56 [123]
F=ma
50=m(5)
m=10kg
hence,ans is B
5 0
3 years ago
Read 2 more answers
Hen a gfci receptacle device is installed on a 20-ampere branch circuit (12 awg copper), what is the minimum volume allowance (i
Bezzdna [24]

Answer:

2.25in³

Explanation:

For a 12 awg conductor the minimum volume allowance as stated by the NEC is 2.25in³

See attached Table 314.16(B) from NEC 2011

4 0
3 years ago
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