El kilogramo de fuerza, o kilopond, es una unidad de fuerza métrica gravitacional. Es igual a la magnitud de la fuerza ejercida sobre un kilogramo de masa en un campo gravitatorio de 9.80665 m / s².
Answer:
Explanation:
Givens
The frequency is defined by
Where 
is the speed of the wave in the string and 
is its wave length.
The wave length is defined as 
Now, to find the speed, we need the tension of the wire and its linear mass density
Where 
and the tension is defined as 
Replacing this value, the speed is
Then, we replace the speed and the wave length in the first equation
Therefore, the frequency is
Answer:
34 m/s
Explanation:
Potential energy at top = kinetic energy at bottom + work done by friction
PE = KE + W
mgh = ½ mv² + Fd
mg (d sin θ) = ½ mv² + Fd
Solving for v:
½ mv² = mg (d sin θ) − Fd
mv² = 2mg (d sin θ) − 2Fd
v² = 2g (d sin θ) − 2Fd/m
v = √(2g (d sin θ) − 2Fd/m)
Given g = 9.8 m/s², d = 150 m, θ = 28°, F = 50 N, and m = 65 kg:
v = √(2 (9.8 m/s²) (150 m sin 28°) − 2 (50 N) (150 m) / (65 kg))
v = 33.9 m/s
Rounded to two significant figures, her velocity at the bottom of the hill is 34 m/s.
A.is an example of decomposition reaction.
