Plz help. Thank youuu

Officer Brimberry wrote 32 tickets for traffic violations last week, but only 12 tickets this week. What is the percent decrease

kolbaska11 [484]

Answer:

62.5 %

Step-by-step explanation:

you have to subtract 32-12, which equals 20

then divide 20 by the original amount (20/32)

20/32= .625, then you have to multiply to get the final answer...hope this helped!

4 0

2 years ago

Determine the period of each function. Show Work plzzz

suter [353]

For determining the period of a function, you pick two recognizable tops of the graph and calculate the time difference between them. In this situation the period is 5-1=4, by picking the first two tops

7 0

2 years ago

What is the radical form for 2 1/2

adelina 88 [10]

Answer:

it would be √2 or 1.41421356

Step-by-step explanation:

its correct

4 0

3 years ago

Solve -2x+3y=-9 4x-6y=2

mr Goodwill [35]

Step-by-step explanation:

Given,

-2x + 3y = -9 ------- (eqⁿ 1)

4x - 6y = 2 ----------- (eqⁿ 2 )

now,

multiply eqⁿ 1 by 2

so we got,

-4x + 6y = -18 -------- (eqⁿ 3)

now,

subtract eqⁿ 2 from eqⁿ 3

we got,

-8x = -16

x = -16/-8

x = 2,

so , after putting values in the eqⁿ 2

we got,

4(2) - 6y = 2

8 - 6y = 2

6y = 2 - 8 = 6

y = 6/6

y = 1

x = 2 and y = 1

hope this answer helps you dear...take care!

7 0

3 years ago

1 The prism-shaped roof has equilateral triangular bases. Use the model you created in question #1 to calculate the height of th

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

Step-by-step explanation: As shown in the attached figure, the prism-shaped roof has equilateral triangular bases, one of which is ΔABC. We need to create an equation that models the height of one of the roof's triangular bases in terms of its sides. Let ii be AD.

See the figure attached herewith, ΔABC forms an equilateral triangle, in which AD is the height. So, D will be the mid-point of BC and ∠ADB = ∠ADC = 90°.

Now, in ΔADB, we have

AD^2=AB^2-BD^2

AD^2=AB^2-(1/2AB^2)^2

AD=√3/4AB^2

we can find the height of any one of the roof's triangular bases.

2.1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythagorean theorem, as shown in the picture, the height is √3/2a

2. if a=25 ft, then the height is √3/2a=√3/2*25=1.732/2*25=21.7(ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l

the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is 2*(1/2*a*√3/2a)=√3/2a^2

so the total area of the roof is

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.

So the total area found previously will be decreased by al

5. so the area now is √3/2a^2 + 2al

6. now a=25 and l=2a=50

Area= √3/2a^2+2al=√3/2*25^2+2*25*50=25^2(√3/2+4)=625*4.866

=3041.3 (ft squared)

6 0

3 years ago