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3 years ago

Please I need help for m quiz

Mathematics

1 answer:

strojnjashka [21]3 years ago

6 0

Answer:

I know it 4 for a fact

Step-by-step explanation:

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The cost of watching videos on a website is represented by C(a) = 3.00a + 4.00, where a is the number of videos watched. The cos

aksik [14]

Answer:

The answer is A; H(a) = 3.00a +19.00; shift 15 units up

Step-by-step explanation:

If the downloading feature is enabled the cost function becomes H(a) = 3.00a + 19.00

The y-interpret of H(a) is 15 greater than the y-intercept if C(a)

The slopes of both functions are the same

3 0

3 years ago

Derivative of tan(2x+3) using first principle

kodGreya [7K]

$f(x)=\tan(2x+3)$

The derivative is given by the limit

$f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h$

You have

$\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h$
$\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h$

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

$\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}$

By this identity, you have

$\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}$

So in the limit you get

$\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h$
$\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}$
$\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}$
$\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}$
$\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}$

The first two limits are both 1, and the single term in the last limit approaches 0 as $h\to0$ , so you're left with

$f'(x)=\dfrac12\sec^2(2x+3)$

which agrees with the result you get from applying the chain rule.

7 0

3 years ago

PLEASE HELP ME FAST WITH THE CORRECT ANSWER!!!!

Scorpion4ik [409]

Its 144. you just subtract the 121 from 265.

4 0

3 years ago

If 9a + 9b + 9c = 59a+9b+9c=5 ,<br><br>what is 72a + 72b + 72c72a+72b+72c?

Gekata [30.6K]

Answer:

Step-by-step explanation:

9a + 9b + 9c = 5

Multiply the equation by 8

8*(9a + 9b + 9c )= 5*8

Distribute

72a +72b +72 c = 40

6 0

4 years ago

PLEASE HELP 30 POINTS

ki77a [65]

4

one of the functions equals 0 while the other equals 4

0+4=4

8 0

3 years ago

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