Answer: this is so zenskinsta can have brainliest
Step-by-step explanation:
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Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
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(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
35z^4 + 11z^4<span>
= 46z^4 ...combine like terms
hope that helps</span>
Given:
Volume of the prism = 60 in³
Breadth = 2.5 in
Height = 4 in.
To find:
The length of the prism.
Solution:
We know that, volume of a prism is

where, l is length, b is breadth and h is height.
Putting V=60, b=2.5 and h=4, we get


Divide both sides by 10.


Therefore, the missing dimension of the prism is 6 in.