Find the base of an isosceles triangle whose area is 12 cm square and one of the equal sides is 5cm.
1 answer:
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Answer:
3.7feet
Step-by-step explanations
Using the sin rule
A/sin a = B/sin b
Let A = PQ = 8.5feet
B = QR = x feet
a = R = 90°
b = P = 26°
Substitute the values into the Sin rule
8.5/sin90 = x/sin26
8.5×sin 26 = x × sin 90
8.5×0.4383 = x× 1
3.7255 = x
Hence the length of QR to the nearest tenth 3.7feet
