The second object, the one that had twice the force applied to it, would move twice as far, I believe.
In 2 days there are 48 hours
to find the average speed per hour, divide 2,387 by 48
Which gets you the answer 49.72
Which rounds up to 50
The average speed is 50mph
Answer:
The maximum height reached by the ball is 20.4 m.
Explanation:
We have,
Mass of a ball is 15 kg
It is thrown straight upward with a speed of 20 m/s.
It is required to find the maximum height reached by the ball. Let the maximum height is h. As energy is conserved, the potential energy at the ball's highest point is equal to the kinetic energy when it is thrown. So,
![mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(20)^2}{2\times 9.8}\\\\h=20.4\ m](https://tex.z-dn.net/?f=mgh%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5Ch%3D%5Cdfrac%7Bv%5E2%7D%7B2g%7D%5C%5C%5C%5Ch%3D%5Cdfrac%7B%2820%29%5E2%7D%7B2%5Ctimes%209.8%7D%5C%5C%5C%5Ch%3D20.4%5C%20m)
So, the maximum height reached by the ball is 20.4 m.
The correct option is this: KINETIC ENERGY JUST BEFORE REACHING THE GROUND IS LESS THAN THE GRAVITATIONAL POTENTIAL ENERGY AT THE TOP OF THE BUILDING.
When the object was on the top of the building, it has potential energy. This potential energy was converted to kinetic energy when the object started falling. In the process of falling, friction was present, which means that some of the energy will be converted to heat as a result of the friction. Therefore the kinetic energy of the falling object will be less than its potential energy, because some of the energy has been spent on friction.<span />