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Serga [27]
3 years ago
14

What kind of quantity is displacement?

Physics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

calar quantity, length of path. displacement: vector quanity, "as the crow flies" difference between start and finish regardless of path taken. Term.

Explanation:

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1. A giri rides her bike at 15 m/s for 20 s. How far does she travel in that time?
Svetach [21]

Answer:

300m

Explanation:

distance=speed x time

=15 x 20

= 300m

6 0
3 years ago
Read 2 more answers
A positively charged rod is brought close to one end of an uncharged metal rod but does not actually touch it. What type of char
svlad2 [7]

Answer:

The end of the neutral rod which is the closest part to the charged rod would acquire a negative charge.

Explanation:

One of the rods is positively charged and one of them is neutral.

And the important part is that <u>they do not touch one another</u>, but get close to each other.

In this case, the end of the neutral rod which is the closest part to the charged rod would acquire a negative charge. This is because of the Coulomb's Law. The opposite charges exert an attractive force to each other. The positive charges attract the negative charges on the neutral rod.

7 0
3 years ago
Two or more different monomers will link to form a
-BARSIC- [3]

d. natural gas is the answer

7 0
2 years ago
How to change the amount of charge to increase the current​
tensa zangetsu [6.8K]

Answer:

Since formula for current is

I = Q/t

or

Current = Charge / Time

to increase current, the charge must be increased per unit time.

5 0
3 years ago
A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline o
storchak [24]

Answer:

Explanation:

The sum of the pore along the plane is expressed according to Newton's law

Fn-Ff = ma

Fn is the moving force

Ff = nR = frictional force

m is the Mass

a is the acceleration

Substitute the given values

Fn - nR = ma

Fn - tan31°(mgcostheta) =3.9(9.8)

Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)

Fn - tan31(38.22cos31)= 38.22

Fn - 32.76tan31 = 38.22

Fn-19.68 = 38.22

Fn = 38.22+19.68.

Fn = 57.90N

Hence Fn (moving force) of the inclined block is 57.90

4 0
3 years ago
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