All categories

2 years ago

A race car is traveling at a constant speed of 200 miles per hour ( mph). How many miles will it travel in three hours?

Mathematics

2 answers:

german2 years ago

5 0

Answer:

600 miles.

Step-by-step explanation:

You just multiply 200 by three.

ira [324]2 years ago

5 0

Answer:

The reason is that 1mile is 200 so 200 times 3 is 600miles

You might be interested in

What algebraic expression represents the phase “two times the quantity of a number minus 12”

MakcuM [25]

Answer:

2(n-12)

Step-by-step explanation:

3 0

3 years ago

Drag expressions to complete each equation.

Maru [420]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

$a^{b}$ × $a^{c}$ = $a^{b+c}$

$\frac{a^{b} }{a^{c} }$ = $a^{b-c}$

$a^{c}$ × $b^{c}$ = $(ab)^{c}$

7 0

2 years ago

Read 2 more answers

PLZ HELP AS FAST.

ivanzaharov [21]

Answer

the triangle on the bottom left has the greatest area

Step-by-step explanation

first one has an area of 24.5

second one has an area of 19.6

the third one has an area of 27.6 (greatest area)

19.6>24.5>27.6

hope this helped!

have an awesome day :D

5 0

2 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago

You have $250. You spend 45% of that. how much is left?

tekilochka [14]

$137.5 is left from spending 45% of $250

8 0

2 years ago