All categories

2 years ago

ANSWER ASAP ( Remember to pull out the GCF or you will get it wrong)

Mathematics

2 answers:

EleoNora [17]2 years ago

5 0

Answer:

Step-by-step explanation:

dimaraw [331]2 years ago

4 0

A I believe please let me know

You might be interested in

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

Sorry last one :Multiply.<br><br> 2√⋅5√⋅11

DIA [1.3K]

Hey! You just have to square root the 2 and 5 then multiply by 11 so the answer I came up with is 34.78505426185218

I hope I helped!

4 0

3 years ago

Read 2 more answers

Three boxes of cereal weigh 379.4 grams,424.25 grams,and 379.37 grams. What is the difference between the lightest and the heavi

TiliK225 [7]

Answer:

44.88

Step-by-step explanation:

Heaviest box = 424.25

Lightest box = 379.37

424.25 - 379.37 = 44.88

Hope this helps!

8 0

3 years ago

The perimeter of the triangular park shown on the right is 10x - 3. What is the missing length?

viva [34]

Answer:

6x - 1

Step-by-step explanation:

Okay this is basically polynomial algebra:

1. Add the value of the lengths already given.

like terms: 3x + x = 4x, -4 + 2 = -2. Now you're left with, 4x - 2.

2. Find the difference between the perimeter and the sum of the lengths.

(10x -3) + (4x + 2) = 6x - 1

4 0

3 years ago

Which of the following is NOT a linear factor of the polynomial function?

Natalija [7]

Answer:

Among the four choices, $(x + 5)$ is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let $a$ denote some constant. A linear factor of the form $(x - a)$ is a factor of a polynomial $f(x)$ if and only if $f(a) = 0$ (that is: replacing all $x$ in the polynomial $f(x) \!$ with the constant $a\!$ would give this polynomial a value of $0$ .)

For example, in the second linear factor $(x - 2)$ , the value of the constant is $a = 2$ . Verify that the value of $f(2)$ is indeed $0$ . (In other words, replacing all $x$ in the polynomial $f(x) \!$ with the constant $2$ should give this polynomial a value of $0\!$ .)

$\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}$ .

Hence, $(x - 2)$ is indeed a linear factor of polynomial $f(x)$ .

Similarly, it could be verified that $(x - 5)$ and $(x + 2)$ are also linear factors of this polynomial function.

Rewrite the first linear factor $(x + 5)$ in the form $(x - a)$ for some constant $a$ : $(x + 5) = (x - (-5))$ , where $a = -5$ .

Calculate the value of $f(5)$ .

$\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}$ .

$f(5) \ne 0$ implies that $(x - (-5))$ (which is equivalent to $(x + 5)$ ) isn't a linear factor of this polynomial function.

3 0

3 years ago