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2 years ago

7. One way to isolate metals from their ores is to react the metal oxide with carbon as shown in the

Chemistry

1 answer:

anyanavicka [17]2 years ago

7 0

Metal oxides react with carbon and are reduced to the metal. The metal in the reaction above is copper.

The equation of the reaction is;

2MO(s) + C(s) -> 2M(s) + CO2(g)

We are told in the question that carbon is in excess so the metal oxide is the limiting reactant.

Number of moles of metal oxide = 34.49 g/M + 16

From PV = nRT

P = 1.50 atm

V = 4.42 L

T = 100°C + 273 = 373 K

n =?

R = 0.082 atmLK-1mol-1

n = PV/RT

n = 1.50 atm × 4.42 L/0.082 atmLK-1mol-1 × 373 K

n = 6.63/30.58

=0.217 moles

If 2 moles of metal oxide yields 1 mole of CO2

34.49 g/M + 16 yields 0.217 moles of CO2

34.49 g/M + 16 = 2 × 0.217

34.49 /M + 16 = 0.434

34.49 = 0.434(M + 16)

34.49 = 0.434M + 6.944

M = 34.49 - 6.944/0.434

M = 63.5

The metal is copper.

Learn more: brainly.com/question/22824409

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$Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}$

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The net ionic equation is as follows.

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Putting values in above equation, we get:

$4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s$

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