Question

What is the volume of 120 x 1022 molecules of nitric oxide gas, NO, at si B) 2.24L C) 0.0199 L D) 5.02 A) 1120 L

Answer 1

Answer: 44.8 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

Standard condition of temperature (STP)  is 273 K and atmospheric pressure is 1 atm respectively.  

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadro's number}}=\frac{120\times 10^{22}}{6.023\times 10^{23}}=2moles$

1 mole of $NO$ occupies volume = 22.4L at STP

Thus 2 moles of magnesium react with=$\frac{22.4}{1}\times 2=44.8L$

Thus the volume of $120\times 10^{22}$ molecules of nitric oxide gas is 44.8 L.