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2 years ago

Which is colder -3°c or -2°c

Mathematics

2 answers:

emmainna [20.7K]2 years ago

5 0

-3°C is the coldest temperature

Karo-lina-s [1.5K]2 years ago

3 0

Answer:

-2 is colder

Step-by-step explanation:

Becuase when you get to the negative the Closest number to 0 is greater which means -2 is closer to 0 which makes it colder.

(Hope this helps can I pls have brainlist (crown)☺️)

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Which would best display the following data if you wanted to display the numbers which are outliers as well as the mean? [4, 1,

Serhud [2]

Arranging data in ascending order to identify the outlier and calculate the mean

Step-by-step explanation:

Given the data as: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

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[1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

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3 years ago

On the packaging for a triangular sail, the edge measurements for the sail are listed as 7 ft × 15 ft × 17 ft. Without unfurling

ASHA 777 [7]

Answer:

Shape of Triangular sail is Obtuse Angled Triangle.

Step-by-step explanation:

The triangle is obtuse since the sum of the squares of 2 sides are greater than the square of the third side. (Converse Pythagorean theorem) Hope this helps!

Given: Length of sides of triangular sail = 7 ft , 15 ft , 7 ft

To find: Shape of Sail .i.e., shape of triangle

We use a result which states that

if a , b , c are sides of triangle where c is greater then a & b.

now, if c² < a² + b² then triangle is Acute angled

if c² = a² + b² then triangle is Right angled

if c² > a² + b² then triangle is Obtuse angled

here a = 7 , b = 7 & c = 15

c² = 15² = 225

a² + b² = 7² + 7² = 49 + 49 = 98

since, c² > a² + b²

⇒ Triangle must be Obtuse Angled.

Therefore, Shape of Triangular sail is Obtuse Angled Triangle.

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3 years ago

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Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?

monitta

Answer:

$(x-7)^2+(y-2)^2=34$

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (7, 2), h = 7 and k = 2. Substitute:

$(x-7)^2+(y-2)^2=r^2$

Next, the since a point on the circle is (2, 5), y = 5 when x = 2. Substitute:

$(2-7)^2+(5-2)^2=r^2$

Solve for r:

$(-5)^2+(3)^2=r^2$

Simplify. Thus:

$25+9=r^2$

Finally, add:

$r^2=34$

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

$(x-7)^2+(y-2)^2=34$

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