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Monica [59]
3 years ago
5

Two hundred grams of a substance requires 9.76kj of heat to raise its temperature from 25 C to 45 C. It has a specific heat of 2

.44J/g. Use the table to identify the substance.
A Ethanol
B Gasoline
C Ice
D Air
I think it's gasoline!

Chemistry
2 answers:
yulyashka [42]3 years ago
7 0
B. Gasoline
hope this helps.
elena55 [62]3 years ago
7 0
Its gasoline im sure ...
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Sdfsdfsdfsfsdfsdfdfdre
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Answer:

310 mmHg

Explanation:

All you have to do here in order to figure out the pressure exerted by gas  

D  is use Dalton's Law of Partial Pressures.

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Is pentacosane a molecular compound?
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Yes

Explanation:

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Answer:no

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3 years ago
Which scenario is most similar to the type of collision that gas particles have according to kinetic molecular theory?
Ugo [173]
I’m not for sure but I think it’s A.
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Read 2 more answers
In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi
mart [117]

The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
  • Molarity of acid, HCOOH (Ma) = 0.4 M
  • Volume of acid, HCOOH (Va) = 50 mL
  • Molarity of base, LiOH (Mb) = 0.15 M
  • Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

8 0
2 years ago
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