I think it's true because its the same data set just put in order backwards.
Hope this helps!! :-)
Answer:
(B)
Step-by-step explanation:
v^2 = v0^2 + 2ax
a = (v^2 - v0^2) / 2x
= (20^2 - 10^2) / 200
= 1.5 m/s
<h3>
Answer: 1.21</h3>
Work Shown:
z = (x - mu)/sigma
z = (72.4 - 69.0)/(2.8)
z = (3.4)/(2.8)
z = 1.2142857 .... which is approximate
z = 1.21
