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horsena [70]
4 years ago
13

The equation below shows hydrogen reacting with oxygen to produce water. 2H2 + O2 2H2O If 16 mol of oxygen were reacted with exc

ess hydrogen gas, how many moles of water would be produced? 4.0 mol 8.0 mol 16 mol 32 mol
Chemistry
2 answers:
omeli [17]4 years ago
6 0

The answer would be 32mol

antoniya [11.8K]4 years ago
6 0

Answer : The moles of water produced will be, 32 moles

Explanation : Given,

Moles of oxygen = 16 moles

The given balanced chemical reaction is:

2H_2+O_2\rightarrow 2H_2O

From the balanced chemical reaction we conclude that,

As, 1 mole oxygen react to give 2 moles of water

So, 16 moles oxygen react to give 2\times 16=32moles of water

Therefore, the moles of water produced will be, 32 moles

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Some covalent compounds dissociate into ions in water. What atom do these compounds have in their structures? What type of solut
valentina_108 [34]

H atoms are found in the molecules of covalent compounds that dissolve in water. These compound are called acids (proton donors). They form acidic solutionst{acidic solutions} acidic solutions.

Because there are no ions moving about in solution with covalent molecules, they are characterised as non-electrolytes. Non-electrolyte solutions are those that do not conduct electricity.

Examples are hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid solutions (HNO3).

<h3>What type of compounds dissociate in water to form ions?</h3>

When certain substances dissolve in water, they undergo either a physical or a chemical change that results in the formation of ions in solution. These substances are members of an important class of compounds known as electrolytes. Nonelectrolytes are substances that do not produce ions when dissolved.

A substance is known as a strong electrolyte if the physical or chemical process that generates the ions is essentially 100% efficient (all of the dissolved compound yields ions). A weak electrolyte is one in which only a small portion of the dissolved substance undergoes the ion-producing process.

learn more about Covalent refer

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3 0
2 years ago
What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2
Anarel [89]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

3 0
3 years ago
How many moles of nh3 can he produced from the reaction of 38 g of n2
fiasKO [112]
N₂ + 3 H₂ → 2 NH₃

number of moles of N₂ = 38 g / 28 g/mol = 1.357 mol

1 mole of N₂ gives 2 moles of NH₃
1.357 mol of N₂ will give ?? mole NH₃

= 2 x 1.357 = 2.7 mol NH₃
5 0
4 years ago
A gas sample is held at constant pressure. The gas occupies 2.97 L of volume when the temperature is 21.6°C. Determine the tempe
STALIN [3.7K]

Answer:

339.2K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 2.97 L

V2 = 3.42 L

T1 = 21.6°C = 21.6 + 273 = 294.6K

T2 = ?

Using V1/T1 = V2/T2

2.97/294.6 = 3.42/T2

Cross multiply

2.97 × T2 = 294.6 × 3.42

2.97T2 = 1007.532

T2 = 1007.532 ÷ 2.97

T2 = 339.236

The final temperature is 339.2K

5 0
3 years ago
1. According to the equation, what mass of hydrogen fluoride is necessary to produce 2.3 g of sodium fluoride?
Luba_88 [7]

Answer:

1.09 grams

Explanation:

According to the following chemical equation:

HF + NaNO₃ -> HNO₃ + NaF

1 mol of hydrogen fluoride (HF) produces 1 mol of sodium fluoride (NaF). Thus, we first convert from mol to grams by using the molar mass (MM) of each compound:

MM(HF)= (1 g/mol x 1 H) + (19 g/mol x 1 F) = 20 g/mol HF

1 mol HF x 19.9 g/mol HF = 20 g

MM(NaF) = (23 g/mol x 1 Na) + (19 g/mol x 1 F) = 42 g/mol NaF

1 mol NaF x 42 g/mol NaF = 42 g

Thus, from 20 g of HF are produced 42 g of NaF  ⇒ 20 g HF/42 g NaF. We multiply this stoichiometric ratio by the mass of NaF produced to calculate the required mass of HF:

20 g HF/42 g NaF x 2.3 g NaF = 1.09 g HF

Therefore, 1.09 grams of HF are necessary to produce 2.3 g of NaF.

5 0
3 years ago
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