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3 years ago

Defined the following convection

Chemistry

1 answer:

photoshop1234 [79]3 years ago

7 0

Answer:

Convection is the process of heat transfer in which hotter and therefore less dense matter floats to the top, while cooler and therefore more dense material sinks to the bottom to absorb heat.

Explanation:

Convection is one form of heat transfer; other forms include conduction and (heat) radiation (not exactly the same as the kind uranium emits).

This form of heat transfer is characterised by a use of current in a liquid, in which the sinking and rising create a current which has a shape of a loop.

This requires an outside source of heat, since to sustain the current, once the heated fluid rises up, it must lose heat to the environment to sink, but to rise it must gain heat again.

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What is the precipitation reaction of sodium nitrate and lead (II)?

Vadim26 [7]

The precipitation reaction of sodium nitrate and lead (II) chloride would not happen. No reaction will happen between these substances. Hope this answers the question. Have a nice day.

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3 years ago

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Vanyuwa [196]

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3 years ago

Read 2 more answers

An acidic fog in pasadena was found to have a ph of 2.50. which expression represents this ph measurement?

joja [24]

Supposing a temperature of 25 degrees and supposing that all activity coefficients are 1

pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14

Thus a pH of 2.50 would mean that the [H+], the concentration of the hydrogen ion, would be 10^(-2.50)

pH + pOH = 14
pOH = 14 - pH = 14 - 2.5 = 11.5
MOH- levels would be coordinated with pOH
pOH = -log[OH-] ==> [OH-] = [MOH-] = 10^-pOH = 10^-11.5 = 3.2 x 10^-12

Therefore, MOH¯ = 3.2 × 10¯12 M

5 0

3 years ago

The Henry's law constant (kH) for O2 in water at 20°C is 1.28 × 10−3 mol/(L·atm). (a) How many grams of O2 will dissolve in 4.00

Burka [1]

Answer:

Solubility of O₂(g) in 4L water = 3.42 x 10⁻² grams O₂(g)

Explanation:

Graham's Law => Solubility(S) ∝ Applied Pressure(P) => S =k·P

Given P = 0.209Atm & k = 1.28 x 10⁻³mol/L·Atm

=> S = k·P = (1.28 x 10⁻³ mole/L·Atm)0.209Atm = 2.68 x 10⁻³ mol O₂/L water.

∴Solubility of O₂(g) in 4L water at 0.209Atm = (2.68 x 10⁻³mole O₂(g)/L)(4L)(32 g O₂(g)/mol O₂(g)) = 3.45 x 10⁻² grams O₂(g) in 4L water.

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3 years ago

Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.

vlada-n [284]

Answer:

2.03

Explanation:

Let's assume we have 1 L of the solution:

There would be 2.07 ethylene glycol moles.

The solution would weigh (1000 mL * 1.02 g/mL) = 1020 g.

With that information we can calculate the molality:

molality = moles of solute / kg of solvent

molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

3 0

2 years ago