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klio [65]
3 years ago
7

This is me smash or pass

Chemistry
1 answer:
Reptile [31]3 years ago
3 0
Smash, but not rlly bc you look too young for me loll
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All the questions to The power of advertising commonlit answers.
NemiM [27]
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8 0
3 years ago
The heat change that accompanies the formation of 1.00 mol of carbon dioxide from its elements is −393.7 kJ/mol. What heat chang
gladu [14]

Answer:

-248.425 kJ/mol

Explanation:

This question can be done by simply taking the ratios:

Since the given the heat change for 1.00 mol of CO_2 is -373.7 KJ/mol. Let us consider the required Heat Exchange at 0.631 mol of

We can write:

\frac{-373.7} {1.00} = \frac{x}{0.631}

x = ( -373.7)(0.631)

x = -248.425 KJ/mol

7 0
3 years ago
I need to know the answers to this I don’t understand it
Anestetic [448]
11) Tornado Valley
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3 0
3 years ago
The reaction between aluminum and copper nitrate is a (A. Combustion, B. Decomposition. C. Double displacement D. Single Displac
salantis [7]

Answer:

D. Single Displacement

C. More reactive than

Explanation:

Al + CuSO₄  --->  Cu + Al₂(SO₄)₃

The aluminum replaces the copper in the compound, isolating copper. This occurs because the aluminum is more reactive than the copper.

I hope this helps! :)

5 0
4 years ago
How fast should you heat the melting point sample?
hichkok12 [17]

Answer:

Option a.

Explanation:              

The transformation of a solid into liquid is a slow process, hence a rate of heating too fast, near the melting point of the sample, will not give the right time to the crystals of the sample to absorb the heat and to melt in the outside and the inside, leading to wrong results in all cases. If we heat to fast, the melting point range will be too broad and will be misleading, resulting in values of the range more hight than the theoric ones.  

A rate of 1 °C/min or 2 °C/min is the most appropriate to approach the melting point of the sample. Since it is too slow, from preventing the experiment taking forever it is recommended to start the experiment at a high heating rate until it reaches 20 °C below the melting point, and then, turn the heating rate down to 1 °C/min or 2 °C/min.      

Therefore, the correct answer is a: near the melting point of the sample, we must heat slowly until it reach the expected temperature.

I hope it helps you!

7 0
3 years ago
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