The magnetizing current in a transformer is rich in 3rd harmonic. This is because harmonics are AC voltages and currents with frequencies that are generally higher.
Answer:
D. two positively charged objects
m = mass of the car moving in horizontal circle = 1750 kg
v = Constant speed of the car moving in the horizontal circle = 15 m/s
r = radius of the horizontal circular track traced by the car = 45.0 m
F = magnitude of the centripetal force acting on the car
To move in a circle . centripetal force is required which is given as
F = m v²/r
inserting the above values in the formula
F = (1750) (15)²/(45)
F = (1750) (225)/(45)
F = 1750 x 5
F = 8750 N
Answer:
Incomplete question: The masses of the blocks m₂ = 1.5 kg and m₃ = 2 kg
Explanation:
Given data:
L₁ = length = 0.85 m
L₂ = 0.25 m
L₃ = 0.5 m
m₂ = 1.5 kg
m₃ = 2 kg
Question: Find the unknown mass of the block 1 needed to balance the bar, m₁ = ?
The torque is zero (intermediate point of the bar)

Is negative because mass 1 is to the left of the coordinate system (see the diagram)

Answer:
∑F = 10.2 N
Explanation:
We have:
Initial velocity: 0.5 m/s
Final velocity: 3 m/s
Time: 1.5 s
We have all of the components needed to calculate acceleration. Let's do that, shall we?
a = vf-vo/t
a = 2.5/1.5
a = 1.7
/
Now, look at the Net Force equation:
∑F = ma
Plug in the variables, to get:
∑F = (6)(1.7)
∑F = 10.2 N (You can round this according to significant digits)