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timofeeve [1]
3 years ago
11

Type the correct answer in the box. Use numerals instead of words. Frank has a sample of steel that weighs 80 grams. If the dens

ity of his sample of steel is 8 g/cm3, what is the sample's volume? The sample's volume is cm3.
Physics
1 answer:
ad-work [718]3 years ago
8 0

Answer:

10cm^3

Explanation:

Given data

Mass of steel = 80grams

density of steel= 8 g/cm^3

We know that the formula for density is given as

density= mass/volume

make volume subject of formula

volume= mass/density

volume=80/8

volume= 10cm^3

Hence, the volume 10cm^3

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8 0
3 years ago
Which alkali metal is most reactive<br>​
Doss [256]
Francium is the most reactive alkali metal
8 0
2 years ago
A concave lens has a focal length of -31 {cm}. Find the image distance and magnification that results when an object is placed 2
kolezko [41]

Answer:

The value is v  =  440 \  cm

and  

 m  =  16

Explanation:

From the question we  are told that

    The image  distance is  v  =  29 \  cm

    The focal length is f =  -31 \  cm

From the lens equation we have that

      \frac{1}{f}  =  \frac{1}{v}  - \frac{1}{u}

=>    \frac{1}{-31}  =  \frac{1}{v}  - \frac{1}{29}

=>     v  =  450 \  cm

Generally the magnification  is  

      m  =  \frac{v}{u}

=>    m  =  \frac{ 450}{29}

=>    m  =  16

7 0
3 years ago
A softball is thrown from the origin of an X-Y coordinate system with an initial speed of 18 m/s at an angle of 35 degrees above
Goshia [24]
Vo = 18 m/s
angle 35 degrees

1) Components of the initial velocity
 
Vox = Vo*cos(35) = 18*cos(35) m/s = 14.74 m/s
Voy = Vo* sin(35) = 18*sin(35) m/s = 10.32 m/s

2) Equations of postion:

x = Vox*t
y = Voy*t - gt^2 / 2

3) Calculations

A) t = 0.5 s, t = 1.0 st = 1.5 s, t = 2.0 s

x = 14.74 * t

t = 0.5 s => x = 14.74 m/s * 0.5s = 7.37 m

t = 1.0 s => x = 14.74 m/s * 1.0s = 14.74 m

t = 1.5s => x = 22.11 m

t = 2s => x = 29.48 m

B)

y = Voy*t - gt^2 / 2

Voy = 10.32 m/s
g = 10 m/s (approximation)

y = 10.32*t - 5t^2

t = 0.5 s=> y = 3.91m

t = 1 s => y = 5.32m

t = 1.5 s => y = 4.23m

t = 2 s => y = 0.64 m



7 0
3 years ago
Two workers are sliding 300 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the ot
romanna [79]

Answer:

The crate's coefficient of kinetic friction on the floor is 0.23.

Explanation:

Given that,

Mass of the crate, m = 300 kg

One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 320 N using a rope connected to the crate.

The crate slides with a constant speed. It means that the net force acting on it is 0. Net force acting on it is given by :

F_1+F_2=\mu N\\\\\mu=\dfrac{F_1+F_2}{mg}\\\\\mu=\dfrac{390+320}{300\times 10}\\\\\mu=0.23

So, the crate's coefficient of kinetic friction on the floor is 0.23.

6 0
3 years ago
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