Ask question

Ask question

All categories

3 years ago

11

Emmy is running a marathon to try to get a Boston qualifying time. She runs at a constant velocity of 6 mph from 7:00 am to 8:30

am.
At 9:00 am, her velocity jumped to 8 mph. She completed her race at 10:30 am at a velocity of 10 mph. Calculate her acceleration
from 9:00 am - 10:30 am.

1 answer:

kondaur [170]3 years ago

4 0

Answer:

answer is c

Explanation:

You might be interested in

If an equivalent (eq) is defined as a mole of charge, what is the concentration of ca2 in blood plasma in eq if its concentratio

Andrei [34K]

The concentration of ca2 in blood plasma is comparable if it is 0.0080, according to the supplied statement.

<h3>How do you quantify concentration?</h3>

Subtract the solute's mass from the total volume of the mixture. Calculate C = m/V, where m is the solute's mass and V seems to be the total volume of such solution. Divide the figures you found for mass and volume to find approximate concentration for your solution.

<h3>What is the definition of concentration in the solution?</h3>

A solution's concentration is a measure of how much solute has been dissolved in a specific amount of the solvent or solution. A concentrated solution contains a significant amount or dissolved solute. A dilute solution is one with a little amount of dissolved solute.

<h3>According to the given data:</h3>

The equivalent weight of detail is the mass that combines with someone or displaces 1.008 grams of molecular hydrogen, or eight.

35.5 grams of chlorine or 0 grams of oxygen.

Those figures are the atomic weight divided by that of the normal valence, which is sixteen in the case of oxygen.

One Ca2+ ion has a charge of +2.Calcium ion concentration:

= 0.0040M ⇒ Ca 2+ Concentration in blood plasma

= 0.0040 × 2⇒ 0.0080 equivalent Ca2

To know more about concentration visit: brainly.com/question/10725862

#SPJ4

7 0

1 year ago

A 1090 kg car moving +11.0 m/s

stiks02 [169]

The mass of the second car is 1434.21 kg

<u>Explanation:</u>

Using law of conservation of momentum,

$m_{1} u_{1}+m_{2} u_{2}=\left(m_{1}+m_{2}\right) v$

Given:

$m_{1}$ = 1090 kg

$u_{1}$ = 11 m/s

$u_{2}$ = 0

v = 4.75 m/s

We need to find $m_{2}$

When substituting the given values in the above equation, we get

$(1090 \times 11)+\left(m_{2} \times 0\right)=\left(1090+m_{2}\right) 4.75$

$11990=5177.5+4.75 m_{2}$

$4.75 m_{2}=11990-5177.5$

$4.75 m_{2}=6812.5$

$m_{2}=\frac{6812.5}{4.75}=1434.21 \mathrm{kg}$

6 0

3 years ago

How to delete question

Marrrta [24]

Oh your from the other question you made I just saw it LOL.
But heres the answer click the 3 dots on the question you made or you can ask a Moderator or Administrator to remove your question with a reason.

6 0

3 years ago

Read 2 more answers

What is the rotational speed of the second hand on a clock that measures the seconds?

pickupchik [31]

Explanation:

Below is an attachment containing the solution

5 0

3 years ago

Several springs are connected as illustrated below in (a). Knowing the individual springs stiffness k1 = 20 N/m, k2 = 30 N/m, k3

Hatshy [7]

Answer:

The equivalent stiffness of the string is 8.93 N/m.

Explanation:

Given that,

Spring stiffness is

$k_{1}=20\ N/m$

$k_{2}=30\ N/m$

$k_{3}=15\ N/m$

$k_{4}=20\ N/m$

$k_{5}=35\ N/m$

According to figure,

$k_{2}$ and $k_{3}$ is in series

We need to calculate the equivalent

Using formula for series

$\dfrac{1}{k}=\dfrac{1}{k_{2}}+\dfrac{1}{k_{3}}$

$k=\dfrac{k_{2}k_{3}}{k_{2}+k_{3}}$

Put the value into the formula

$k=\dfrac{30\times15}{30+15}$

$k=10\ N/m$

k and $k_{4}$ is in parallel

We need to calculate the k'

Using formula for parallel

$k'=k+k_{4}$

Put the value into the formula

$k'=10+20$

$k'=30\ N/m$

$k_{1}$ ,k' and $k_{5}$ is in series

We need to calculate the equivalent stiffness of the spring

Using formula for series

$k_{eq}=\dfrac{1}{k_{1}}+\dfrac{1}{k'}+\dfrac{1}{k_{5}}$

Put the value into the formula

$k_{eq}=\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{35}$

$k_{eq}=8.93\ N/m$

Hence, The equivalent stiffness of the string is 8.93 N/m.

3 0

3 years ago