Ask question

Ask question

All categories

2 years ago

8

microwave ovens emit microwave energy with a wavelength of 12.5 cm. what is the energy of exactly one photon of this microwave r

adiation?

1 answer:

viktelen [127]2 years ago

7 0

Answer:

1.5891x10^-24

hope this helped :)

You might be interested in

A person jumps off a diving board 5.0 m above the water's surface into a deep pool. The person's downward motion stops 2.2 m bel

shutvik [7]

Answer:

9.9 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 5+0^2}\\\Rightarrow v=9.9\ m/s$

If the body has started from rest then the initial velocity is 0. In order to find the velocity just before hitting the water then the distance at which the downward motion stops is irrelevant.

Hence, the speed of the diver just before striking the water is 9.9 m/s

7 0

3 years ago

PLEASE ITS AN Emergency IF ITS RIGHT I WILL GIVE BRAINLIEST

Art [367]

Uh I think it’s point guard

3 0

3 years ago

A child on a swing sweeps out a distance of 45 ft on the first pass. If she is allowed to continue swinging until she stops, an

earnstyle [38]

Answer:

d = 90 ft

Explanation:

Here in each swing the distance sweeps by the swing is half of the initial distance that it will move

So here we can say that total distance in whole motion is given as

$d = 45 + \frac{45}{2} + \frac{45}{4} + \frac{45}{8}..........$

since it is half of the distance that it will move in each swing so it would be a geometric progression with common ratio of 1/2

so sum of such GP is given by the formula

$S = \frac{a}{1 - r}$

$d = \frac{45}{1 - \frac{1}{2}}$

$d = 90 ft$

6 0

3 years ago

A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i

Darya [45]

The position of the first ball is

$y_1=h-\dfrac g2t^2$

while the position of the second ball, thrown with initial velocity $v$ , is

$y_2=vt-\dfrac g2t^2$

The time it takes for the first ball to reach the halfway point satisfies

$\dfrac h2=h-\dfrac g2t^2$

$\implies\dfrac h2=\dfrac g2t^2$

$\implies t=\sqrt{\dfrac hg}$

We want the second ball to reach the same height at the same time, so that

$\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2$

$\implies h=2v\sqrt{\dfrac hg}-g\left(\dfrac hg\right)$

$\implies h=v\sqrt{\dfrac hg}$

$\implies v=\sqrt{hg}$

8 0

3 years ago

How much heat is required to convert 0.3 kg of ice at 0°C to water at the same temperature

madreJ [45]

Answer:

100,800 Jkg

The heat that is used to change the state of a mater is called latent heat.

In this case it is converting ice to water and it is called latent heat of fusion.

It is given by:

Heat = mc

where m is the mass of ice and l is the specific latent heat of fusion of ice.

l = 0.336 MJ

Heat = 0.3 × 0.336 MJ

= 0.3 × 0.336 × 10⁶

= 100,800 Jkg

6 0

3 years ago