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Sergio [31]
3 years ago
9

The force of gravity on Mercury is less than the Earth because:

Physics
2 answers:
drek231 [11]3 years ago
8 0
The answer is B.

Earth's mass is <span>5.972 × 10^24 kg
Mercury's mass is </span><span>3.285 × 10^23 kg

Hope i helped</span>
Vinvika [58]3 years ago
7 0
Mercury has less mass than earth. So the answer is B
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Why does Doug need to adjust his workouts when they seem too easy?
Aleonysh [2.5K]
Doug needs to change the <em>exercises </em>he is doing. Your body begins to become accustomed to what you do, and if you do the same thing every single time - you will stop making progress, and they'll simply become easy.

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When you change it up, your body will react. The goal is to be comfortable being uncomfortable. Also, one of the most overlooked things in working out is the intensity. If you bring it everything you got and go to the last gut wretching rep, you'll see results. 

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6 0
4 years ago
What are six reasons for having goals
ohaa [14]

Answer:

Without a goal, your efforts can become disjointed and often confusing

Helps you measure progress

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Explanation:

Hope this helps!!!!!!!!!!!

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3 0
3 years ago
What is the force exerted by a solid surface that opposes gravity?
jonny [76]

Electromagnetic force between the molecules! 
6 0
3 years ago
Read 2 more answers
If a flea can jump straight up to a height of 0.550 m , what is its initial speed as it leaves the ground?
olga55 [171]
Let u = upward initial speed of the flea.

At the maximum height of h = 0.550 m, the vertical velocity is v = 0.
Therefore, from the formula
 v² = u² - 2gh,
obtain
0 = u² - 2*(9.8 m/s²)*(0.55 m) 
u² = 10.78 m²/s²
 u = 3.283 m/s

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7 0
3 years ago
A ball of mass 24.1 g is attached to a cord of length 0.417 m and rotates in a vertical circle. What is the minimum speed the ba
Karo-lina-s [1.5K]

Answer:

<em>the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

<em></em>

Explanation:

In order to avoid slack, the centripetal force of the ball must equal its weight at the top of the circle. Therefore,

F_c = F_g

m v² / r = m g

v² = g r

v = √[g r]

v = √[(9.8 m/s²)(0.417 m)]

<em>v = 2.02 m/s </em>

Therefore,<em> the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

6 0
3 years ago
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