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3 years ago

A 50.0 kg object is moving at 18.2 m/s when a 200 N force

Physics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a = force ÷ mass

a = $\frac{-200}{50}$ = -4 m/s²

we get here now required time that is

required time = $\frac{V_{(final)} - V_{(initial)}}{a}$ ...............1

put here value

required time = $\frac{12.6-18.2}{-4}$

so distance will be

distance = $\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}$ ........2

distance = $\frac{12.6}^2 -{18.2}^2}{2\times (-4)}$

distance = 21.56 m

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7nadin3 [17]

Answer:

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3 years ago

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Brrunno [24]

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3 years ago

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san4es73 [151]

Answer:

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3 years ago

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NISA [10]

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