Question

A 50.0 kg object is moving at 18.2 m/s when a 200 N force

Answer 1

Answer:

distance = 21.56 m

Explanation:

given data

mass = 50 kg

initial velocity  = 18.2 m/s

force = -200 N ( here force applied to opposite direction )

final velocity = 12.6 m/s

solution

we know here acceleration will be as

acceleration a  = force ÷ mass

a = $\frac{-200}{50}$   =  -4 m/s²

we get here now required time that is

required time = $\frac{V_{(final)} - V_{(initial)}}{a}$     ...............1

put here value

required time = $\frac{12.6-18.2}{-4}$  

so distance will be

distance = $\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}$    ........2

distance = $\frac{12.6}^2 -{18.2}^2}{2\times (-4)}$  

distance = 21.56 m