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2 years ago

Two dogs are pulling on a chew toy. One dog pulls the chew toy with 64 N [E] and

Physics

1 answer:

PIT_PIT [208]2 years ago

3 0

Answer:

Eastward, at 11 m/s^2

Explanation:

64N-31N=unbalanced force of 33N

F=ma

33N=(3kg)a

a=11m/s^2 to the East

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Pls answer quick will mark brainlest and 5 stars

QveST [7]

Answer:A

Explanation:

It’s bigger I am not sure

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3 years ago

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An elevator has a mass of 1000 Kg. What force is needed to accelerate it upward at a rate of 2 m/s/s?

zubka84 [21]

The force needed to accelerate an elevator upward at a rate of $2 m / s^{2}$ is 2000 N or 2 kN.

<u>Explanation: </u>

As per Newton's second law of motion, an object's acceleration is directly proportional to the external unbalanced force acting on it and inversely proportional to the mass of the object.

As the object given here is an elevator with mass 1000 kg and the acceleration is given as $2 m / s^{2}$ , the force needed to accelerate it can be obtained by taking the product of mass and acceleration.

$\text {Force}=\text {Mass} \times \text {Acceleration}$

$\text { Force }=1000 \times 2=2000 \mathrm{N}=2 \text { kilo Newon }$

So 2000 N or 2 kN amount of force is needed to accelerate the elevator upward at a rate of $2 m / s^{2}$ .

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3 years ago

Suppose the odometer on our car is broken and we want to estimate the distance driven over a 30 second time interval. We take th

Natalija [7]

Let say for every 5 s of time interval the speed will remain constant

so it is given as

v(mi/h) 16 21 23 26 33 30 28

now we have to convert the speed into ft/s as it is given that 1 mi/h = 5280/3600 ft/s

so here we will have

v(ft/s) 23.5 30.8 33.73 38.13 48.4 44 41.1

now for each interval of 5 s we will have to find the distance cover for above interval of time

$d = v \times t$

$d = (23.5 + 30.8 + 33.73 + 38.13 + 48.4 + 44 + 41.1) \times 5$

$d = 1298.1 ft$

so here it will cover 1298.1 ft distance in 30 s interval of time

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3 years ago

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classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 128 feet per

ddd [48]

Answer:

$t_1 = 0.28 s$

$t_2 = 7.72 s$

Explanation:

Given that height of the projectile as a function of time is

$h = -16 t^2 + 128 t + 112$

here we know that

h = 147 ft

so from above equation

$147 = -16 t^2 + 128 t + 112$

$16 t^2 - 128 t + 35 = 0$

now by solving above quadratic equation we know that

$t_1 = 0.28 s$

$t_2 = 7.72 s$

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3 years ago

Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of

mario62 [17]

I don't know if you need to complete this question or do it otherwise, however, I managed to find on the Internet on several places this completion of your sentence:
<span>Electric current flows through a long rod generating thermal energy at a uniform volumetric rate of q = 2 x 10</span>⁶ W/m³.
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