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Cerrena [4.2K]
2 years ago
14

Help me with any of these please

Mathematics
2 answers:
Contact [7]2 years ago
8 0
1) 3/2
2) 7/8
3) 1.5
4) 5
6) octagon
7) b * h
kumpel [21]2 years ago
7 0
K, so here we go:
1. 3/4 + 3/4. When adding fractions, you only add the numerator or whole numbers (doesn't have a whole number, but the numerator's are the top numbers) NOT the denominator (bottom number) Add 3+3, and this gives you 6. Keep the 4 the same, and you get 6/4. The answer is 6/4, but you can make this a proper fraction, and say it's 1 and 2/4 (one is the whole number, it's like the 4 in number 3)

2. 2- 1 and 1/8. This is just subtraction, subtract the whole numbers first. 2-1=1. now, assume the 2 is 2 and 0/8, and you just took away 1. Now, it's 1 and 0/8. Now, take away another 1/8 and you get 7/8

3. Just division. The Answer is 3/2, or 1 and 1/2

4. Simple division again. Divide 15 by 3. You get 5. This is 1/3 of 15, because 5*3=15.

5. An 8 sided polygon is known as an octagon. 

6. A=B*H (Area= base times height.)

7. A quarter is 4. It takes 4 quarter pounds to make a pound (think like money. a quarter is 25 cents. it takes 4 quarters to make a dollar. If you want 60 dollars, how many quarters would you need?) Well, take 60*4, and you get 240. You can make 240 quarter pounders from 60 pounds of meat.
___________________________________________________________
 TO CLARIFY:
1= 6/4 OR 1 and 2/4
2= 7/8
3=3/2 OR 1 and 1/2
4=5
5=Octagon. 
6: A=B*H
7. 240 quarter pounders


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Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
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2 years ago
7. Find the measure of one exterior angle of<br><br> the regular polygon.<br><br> Triangle
Phantasy [73]

Answer:120°

Step-by-step explanation:

sum of exterior angles=360

In a triangle we have 3 exterior angles

Size for each exterior angle=360/3

Size for each exterior angle=120°

8 0
2 years ago
Select all of the following statments that are true
Nonamiya [84]

Answer:

A. -¾ + 0 = -¾

B. -¾ - ¾ = -(¾ + ¾)

C. ¾ - ¾ = ¾ + (-¾)

E. -¾ + ¾ = ¾ + (-¾)

F. -¾ + ¾ = 0

Step-by-step explanation:

Let's check each equation to determine whether they are true or false.

If what we have in the both sides are equal, then the equation is true, if they're not, them it is false.

✔️-¾ + 0 = -¾

Add everything on your left together

-¾ = -¾ (TRUE)

✔️-¾ - ¾ = -(¾ + ¾)

Add everything on both sides together respectively

(-3 - 3)/4 = -(3 + 3)/4

-6/4 = -6/4 (TRUE)

✔️¾ - ¾ = ¾ + (-¾)

0 = ¾ - ¾ (+ × - = -)

0 = 0 (TRUE)

✔️-¾ + ¾ = ¾ - (-¾)

0 = ¾ + ¾ (- × - = +)

0 = 6/4 (FALSE)

✔️-¾ + ¾ = ¾ + (-¾)

0 = ¾ - ¾ (+ × - = -)

0 = 0 (TRUE)

✔️-¾ + ¾ = 0

0 = 0 (TRUE)

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A line has the equation 32 - 2y = 1 What is the equation of
mart [117]

Answer:

A = 3; B = -2; C = 2

Step-by-step explanation:

Original line:

3x - 2y = 1

Slope of original line:

-2y = -3x + 1

y = 3/2 x - 1/2

slope = m = 3/2

Parallel lines have equal slopes, so we need the equation of the line with slope 3/2 that passes through the point (-6, -10)

y = mx + b

y = (3/2)x + b

Substitute -6 for x and -10 for y and solve for b.

-10 = (3/2)(-6) + b

-10 + 9 = b

b = -1

Equation: y = (3/2)x - 1

2y = 3x - 2

3x - 2y = 2

4 0
1 year ago
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